7. You are planning a synthesis to transform the following alcohol into a nitrile. However, a hydroxyl group is not a good leaving group in SN2 reactions. How would you solve the probl OH CN Na CN THF OCH3 OCH3
7. You are planning a synthesis to transform the following alcohol into a nitrile. However, a hydroxyl group is not a good leaving group in SN2 reactions. How would you solve the probl OH CN Na CN THF OCH3 OCH3
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:7. You are planning a synthesis to transform the following alcohol into a nitrile. However, a
hydroxyl group is not a good leaving group in SN2 reactions. How would you solve the problem?
OH
CN
Na CN
THF
OCH3
CH3
Better leaving group
Expert Solution

Step 1
Explanation
Nucleophilic substitution reaction
- If one nucleophile replaced by another nucleophile called Nucleophilic substitution reaction.
- Reactivity of nucleophile is called nucleophilicity it is kinetic term but basicity is thermodynamic term.
- In periods nucleophilicity direct prepositional to basicity
- In group nucleophilicity α 1/basicity
-
SN2 reaction
Substrate:
- Best in primary alkyl halide
- Works for secondary alkyl halide, fails if tertiary.
Reaction is:
- Concerted reaction means no intermediate is present, transition state is present and
- it is single step reaction and all bonds are form and break at same time
- This reaction stereospecific reaction that means Walden inversion taking place in this reaction (umbrella).
- Bimolecular reaction: rate depends on concentration of both nucleophile and substrate.
Nucleophile:
- Best if more reactive that means more ionic or more basic.
Leaving group:
- TsO is very good leaving group.
Following orders
TsO › I- › Br- ›Cl- › F- (very poor)
- Basicity order is CH3- › NH2- › OH- ›F-
- Leaving Groups on double-bonded carbons are never replaced by SN2 reaction.
Solvent
- Polar Aprotic (i.e. no OH) is best
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