7. What is the average (rms) drop of potential across the inductor in the circuit shown below? Take R=4022, L=0.5H, C=10 µF, and the voltage varies as V(t)=10V sin(600-t). A. 3.7 V B. 8.5 V C. 12 V D. 15 V E. 22 V V sincot ww 40 Ω 10 uF 0.5 H
7. What is the average (rms) drop of potential across the inductor in the circuit shown below? Take R=4022, L=0.5H, C=10 µF, and the voltage varies as V(t)=10V sin(600-t). A. 3.7 V B. 8.5 V C. 12 V D. 15 V E. 22 V V sincot ww 40 Ω 10 uF 0.5 H
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Question:**
What is the average (rms) drop of potential across the inductor in the circuit shown below? Take \( R = 40 \Omega \), \( L = 0.5 H \), \( C = 10 \mu F \), and the voltage varies as \( V(t) = 10V \cdot \sin(600 \cdot t) \).
- **A. 3.7 V**
- **B. 8.5 V**
- **C. 12 V**
- **D. 15 V**
- **E. 22 V**
**Circuit Diagram Explanation:**
The given circuit is an RLC series circuit, where:
- The resistor (\( R \)) has a resistance of \( 40 \Omega \).
- The inductor (\( L \)) has an inductance of \( 0.5 H \).
- The capacitor (\( C \)) has a capacitance of \( 10 \mu F \).
- The voltage source is an AC source described by the function \( V(t) = 10V \cdot \sin(600 \cdot t) \).
In the diagram:
- The sinusoidal voltage source (represented by a voltage sine wave symbol) is connected in series with the resistor, capacitor, and inductor.
- The resistor (\( 40 \Omega \)) is placed in series before the inductor.
- The inductor (\( 0.5 H \)) and the capacitor (\( 10 \mu F \)) follow in series subsequently.
**Solution Hint:**
To solve this problem, one needs to use the formula for the RMS voltage across the inductor in an RLC series circuit, considering the provided parameters.
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