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7. Using the value given for K, for the equation in Problem 6, at 500°C, calculate (a) Ke for the reaction H2(6) + I) = 2 HI) (b) Keg for the reaction HI) = }H) +12(«) (c) Ke for the reaction H2) + I2) (d) K for the reaction 4 HI 2 H, 3. 2(g) HI) H2)+2 12)

7. Using the value given for K, for the equation in Problem 6, at 500°C, calculate (a) Ke for the reaction H2(6) + I) = 2 HI) (b) Keg for the reaction HI) = }H) +12(«) (c) Ke for the reaction H2) + I2) (d) K for the reaction 4 HI 2 H, 3. 2(g) HI) H2)+2 12)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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6. For the reaction 2 HI = H2) + I2) Keg = 0.016 at 500°C (a) If 1.0 mole of HI is placed in a 2.0-/ container and allowed to come to equilibrium at 500°C, calculate the equilibrium concentrations of H,, I,, and HI. (b) If 0.35 mole of HI is placed in a 0.75-f container and allowed to come to equilibrium at 500°C, calculate the equilibrium concentrations of H, I,, and HI.
Transcribed Image Text:6. For the reaction 2 HI = H2) + I2) Keg = 0.016 at 500°C (a) If 1.0 mole of HI is placed in a 2.0-/ container and allowed to come to equilibrium at 500°C, calculate the equilibrium concentrations of H,, I,, and HI. (b) If 0.35 mole of HI is placed in a 0.75-f container and allowed to come to equilibrium at 500°C, calculate the equilibrium concentrations of H, I,, and HI.
7. Using the value given for Ke, for the equation in Problem 6, at 500°C, calculate (a) Keg for the reaction H2(g) + Iz) = (b) Keg for the reaction HI) = } (c) Ke for the reaction He) + HI (d) K, for the reaction 4 HI 2 HI 2(g) eq 2 H26) +2 12) 8. For the reaction
Transcribed Image Text:7. Using the value given for Ke, for the equation in Problem 6, at 500°C, calculate (a) Keg for the reaction H2(g) + Iz) = (b) Keg for the reaction HI) = } (c) Ke for the reaction He) + HI (d) K, for the reaction 4 HI 2 HI 2(g) eq 2 H26) +2 12) 8. For the reaction
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