7. The vapor pressure of benzene between 10 °C and 30 °C fits the expression1780 Klog()= 7.960-Twhere T is in K. Calculate (a) the enthalpy of vaporization (Avap H) and (b) the normalboiling point of benzene.

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7. The vapor pressure of benzene between 10 °C and 30 °C fits the expression 1780 K log(P) = 7.960- T where T is in K. Calculate (a) the enthalpy of vaporization (AvapH) and (b) the normal boiling point of benzene.

7. The vapor pressure of benzene between 10 °C and 30 °C fits the expression 1780 K log(P) = 7.960- T where T is in K. Calculate (a) the enthalpy of vaporization (AvapH) and (b) the normal boiling point of benzene.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

7. The vapor pressure of benzene between 10 °C and 30 °C fits the expression
1780 K
log()= 7.960-
T
where T is in K. Calculate (a) the enthalpy of vaporization (Avap H) and (b) the normal
boiling point of benzene.

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