7. The height of a helicopter above the ground is given by h =20.0 t-5.0 ť where h is in meters and t is in seconds. At t =1.00 s, the helicopter releases a small mailbag. a) What is speed of a mailbox before hint to the ground? b) How long mailbox in air?

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7. The height of a helicopter above the ground is given by h =20.0 t-5.0 t where h is in meters and
t is in seconds. At t=1.00 s, the helicopter releases a small mailbag.
a) What is speed of a mailbox before hint to the ground?
b) How long mailbox in air?
8. Starting from rest at 5 m from origin, a small still ball's horizontal component of velocity is
90.0 mile/hour in a straight line in 10.0 s. Ball's acceleration is constant during the entire
motion, what is ball's final position?
Transcribed Image Text:7. The height of a helicopter above the ground is given by h =20.0 t-5.0 t where h is in meters and t is in seconds. At t=1.00 s, the helicopter releases a small mailbag. a) What is speed of a mailbox before hint to the ground? b) How long mailbox in air? 8. Starting from rest at 5 m from origin, a small still ball's horizontal component of velocity is 90.0 mile/hour in a straight line in 10.0 s. Ball's acceleration is constant during the entire motion, what is ball's final position?
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Hey there, since you have asked multiple questions. We have answered the first one for you. Please re-post the question and highlight the un-resolved one.

Given :

      Height of the helicopter, h(t) = ( 20 t - 5 t2 ) m 

      At t = 1s, height of the helicopter from ground is h(1) = ( 20(1) - 5(1)2 )

                  h = 15 m 

To determine the speed of the mailbox before hitting the ground and how long was the mailbox in air.

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