**Position vs Time Graph Analysis**1. The position vs time graph of an object is shown below. Answer the questions based on the graph.**Graph Description:**- The graph is titled "Position vs. Time."- The x-axis represents Time (s) ranging from 0 to 2 seconds.- The y-axis represents Position (m) ranging from 0 to 1 meter.- There is a line graph plotted on the grid, illustrating the motion of the object.**Graph Details:**- From 0 to 0.5 seconds, the position increases linearly from 0 m to 0.5 m.- From 0.5 to 1.0 seconds, the position remains constant at 0.5 m.- From 1.0 to 2.0 seconds, the position decreases linearly, returning to 0 m at 2.0 seconds.**Question:**(a) During which interval of time is the particle at rest?- A. 0.0s – 0.5 s- B. 0.5 s – 1.0 s- C. 1.0 – 2.0 s**Explanation:**To determine when the particle is at rest, look for the flat section of the graph where the position does not change. This occurs between 0.5 s and 1.0 s. Therefore, the particle is at rest during interval B. (b) During which interval of time is the particle traveling in the negative direction?- A. 0.0 – 0.5 s- B. 0.5 s – 1.0 s (Selected)- C. 1.0 – 2.0 s(c) In which interval is the speed of the particle the greatest?- A. 0.0 s – 0.5 s- B. 0.5 s – 1.0 s- C. 1.0 – 2.0 s(d) Calculate the velocity between 0.0 s – 0.5 s.\[ v = \, \boxed{\phantom{0}} \, \text{m/s} \]Notes:- There is a handwritten annotation "0.5/3.26" next to question (b).

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Description: **Position vs Time Graph Analysis**1. The position vs time graph of an object is shown below. Answer the questions based on the graph.**Graph Description:**- The graph is titled "Position vs. Time."- The x-axis represents Time (s) ranging from 0 to

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1. The position vs time graph of an object is shown below. Answer the questions based on the graph. OA. 0.0s - 0.5 s OB. 0.5 s - 1.0 s Position (m) OC. 1.0-2.0 s 1 0.9 0.8 0.7- 0.6- 0.5- 0.4- 0.3- 0.2 öö 210 0.1 0 0.8 Time (s) (a) During which interval of time is the particle at rest? Position vs. Time 0 (0.5 s, 0.5 m) (1.0 s, 0.5 m) 0.4 1.2 1.6 2 (

1. The position vs time graph of an object is shown below. Answer the questions based on the graph. OA. 0.0s - 0.5 s OB. 0.5 s - 1.0 s Position (m) OC. 1.0-2.0 s 1 0.9 0.8 0.7- 0.6- 0.5- 0.4- 0.3- 0.2 öö 210 0.1 0 0.8 Time (s) (a) During which interval of time is the particle at rest? Position vs. Time 0 (0.5 s, 0.5 m) (1.0 s, 0.5 m) 0.4 1.2 1.6 2 (

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.

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Question

(b) During which interval of time is the particle traveling in the negative direction?

- A. 0.0 – 0.5 s
- B. 0.5 s – 1.0 s (Selected)
- C. 1.0 – 2.0 s

(c) In which interval is the speed of the particle the greatest?

- A. 0.0 s – 0.5 s
- B. 0.5 s – 1.0 s
- C. 1.0 – 2.0 s

(d) Calculate the velocity between 0.0 s – 0.5 s.

\[ v = \, \boxed{\phantom{0}} \, \text{m/s} \]

Notes:
- There is a handwritten annotation "0.5/3.26" next to question (b).

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