7. The expected number of people showing up for an event has mean 75,000 and variance 5, 000². (a) Give an upper bound on the probability of having fewer than 65,000 or more than 85,000 people? (b) Give an upper bound on the probability of having fewer than 60,000 or more than 90,000 people?
7. The expected number of people showing up for an event has mean 75,000 and variance 5, 000². (a) Give an upper bound on the probability of having fewer than 65,000 or more than 85,000 people? (b) Give an upper bound on the probability of having fewer than 60,000 or more than 90,000 people?
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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![**Problem 7: Probability Upper Bound for Event Attendance**
The expected number of people showing up for an event is characterized by a mean of 75,000 and a variance of \(5,000^2\).
**(a)** What is the upper bound on the probability of having fewer than 65,000 or more than 85,000 people?
**(b)** What is the upper bound on the probability of having fewer than 60,000 or more than 90,000 people?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9e27b5d-0ab8-428e-954d-97d64fc14c61%2F300da1e0-94d2-45ab-9b72-0d8fa50badf9%2Fqkjydjg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 7: Probability Upper Bound for Event Attendance**
The expected number of people showing up for an event is characterized by a mean of 75,000 and a variance of \(5,000^2\).
**(a)** What is the upper bound on the probability of having fewer than 65,000 or more than 85,000 people?
**(b)** What is the upper bound on the probability of having fewer than 60,000 or more than 90,000 people?
Expert Solution
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Step 1
Introduction:
Denote X as the number of people showing up for an event.
It is given that X has a mean of μ = 75,000, and variance of σ2 = 5,0002, so that the standard deviation is, σ = 5,000.
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