7. Math 210- Module 6 - Show all Work - Ask me for help if needed. The sampling distribution of proportions is normal under certain conditions with a mean of p(1-p) H = p and o n Assume the conditions are met. Suppose a weighted coin has a 44.0% chance of getting heads. Use the normal distribution to find the probability that when flipping the coin 110 times the proportion of heads is more than 50.0%.
7. Math 210- Module 6 - Show all Work - Ask me for help if needed. The sampling distribution of proportions is normal under certain conditions with a mean of p(1-p) H = p and o n Assume the conditions are met. Suppose a weighted coin has a 44.0% chance of getting heads. Use the normal distribution to find the probability that when flipping the coin 110 times the proportion of heads is more than 50.0%.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
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![**Math 210 - Module 6: Sampling Distribution of Proportions**
This module covers the sampling distribution of proportions, which is normal under certain conditions.
**Mean and Standard Deviation:**
- The mean (\( \mu_{\hat{p}} \)) of the sampling distribution is equal to the population proportion (\( p \)).
- The standard deviation (\( \sigma_{\hat{p}} \)) is given by:
\[
\sigma_{\hat{p}} = \sqrt{\frac{p(1-p)}{n}}
\]
**Example Problem:**
Assume the conditions are met. Suppose a weighted coin has a 44.0% chance of getting heads. Use the normal distribution to find the probability that when flipping the coin 110 times, the proportion of heads is more than 50.0%.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba09805e-c69e-42c2-a695-6eaaf9d4ee4f%2F16cc926d-bb28-43a1-8017-483e288de8be%2Fi9e4gh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Math 210 - Module 6: Sampling Distribution of Proportions**
This module covers the sampling distribution of proportions, which is normal under certain conditions.
**Mean and Standard Deviation:**
- The mean (\( \mu_{\hat{p}} \)) of the sampling distribution is equal to the population proportion (\( p \)).
- The standard deviation (\( \sigma_{\hat{p}} \)) is given by:
\[
\sigma_{\hat{p}} = \sqrt{\frac{p(1-p)}{n}}
\]
**Example Problem:**
Assume the conditions are met. Suppose a weighted coin has a 44.0% chance of getting heads. Use the normal distribution to find the probability that when flipping the coin 110 times, the proportion of heads is more than 50.0%.
Expert Solution

Step 1: Write the given information.
Given information:
p=The chance of getting heads= 44.0%=0.44
n=number of coins flipped = 110
Therefore,
Step by step
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