Part 1A population of values has a normal distribution with mean of 50.6 and standarddeviation of 98.9.a) Get the z-score for a value of 44. For this problem you use the z score formulab) This z-score tells you how manythe score of 44 is above orbelow the population mean u.c) Find the probability that a randomly selected value is less than 44.

A population of values has a normal distribution with mean of 50.6 ahd stan deviation of 98.9. a) Get the z-score for a value of 44. For this problem you use the z score for b) This z-score tells you how many the score of 44 is above below the population mean u. hility that a randomly selected value is less than 44.

A population of values has a normal distribution with mean of 50.6 ahd stan deviation of 98.9. a) Get the z-score for a value of 44. For this problem you use the z score for b) This z-score tells you how many the score of 44 is above below the population mean u. hility that a randomly selected value is less than 44.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Part 1
A population of values has a normal distribution with mean of 50.6 and standard
deviation of 98.9.
a) Get the z-score for a value of 44. For this problem you use the z score formula
b) This z-score tells you how many
the score of 44 is above or
below the population mean u.
c) Find the probability that a randomly selected value is less than 44.

Expert Solution

Step 1

Given Information:

$μ = 50.6$

$σ = 98.9$

(a) To get the z-score for a value of 44:

Z-score is a measure which tells how many standard deviations away a data value is, from the mean. It is given by the formula:

$Z = \frac{X - μ}{σ}$

where, X is the Raw score

$μ$ is the mean

$σ$ is the standard deviation.

Substitute the given values in the formula:

$\begin{array}{rcl} Z & = & \frac{44 - 50.6}{98.9} \\ = & \frac{- 6.6}{98.9} \\ = & - 0.0667341 \\ \approx & - 0.07 \end{array}$

Thus, z-score for a value of 44 is -0.07

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