Part 1A population of values has a normal distribution with mean of 50.6 and standarddeviation of 98.9.a) Get the z-score for a value of 44. For this problem you use the z score formulab) This z-score tells you how manythe score of 44 is above orbelow the population mean u.c) Find the probability that a randomly selected value is less than 44.

A population of values has a normal distribution with mean of 50.6 ahd stan deviation of 98.9. a) Get the z-score for a value of 44. For this problem you use the z score for b) This z-score tells you how many the score of 44 is above below the population mean u. hility that a randomly selected value is less than 44.

A population of values has a normal distribution with mean of 50.6 ahd stan deviation of 98.9. a) Get the z-score for a value of 44. For this problem you use the z score for b) This z-score tells you how many the score of 44 is above below the population mean u. hility that a randomly selected value is less than 44.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

A normal distribution has mean u = 63 and standard deviation o =20. Find and interpret the z-score for x=57.
answer 3 and 4
Mason earned a score of 226 on Exam A that had a mean of 250 and a standard deviation of 40. He is about to take Exam B that has a mean of 550 and a standard deviation of 25. How well must Mason score on Exam B in order to do equivalently well as he did on Exam A? Assume that scores on each exam are normally distributed.
Given: u = 500 ( Population mean score for a Standardized Biology exam. 0 = 30 (Population mean score for a Standardized Biology exam. %3D Eighty-one (81) scores were selected at random. The mean, X-bar, was calculated. 3. Find P( X-bar 510). . 5. Find P( 480 < X-bar < 520) · Given : The average test score (u) in 2020 of a Standardized Accounting Exam was 550 with a population standard deviation (o) of 45. 6. . Find Lowest Test Score x which is in the 95" Percentile. 7. Find Lowest Test Score x which is in the 75" Percentile. 8. Find Lowest Test Score x which is in the 25" Percentile. 75t 25 that an Independent Education Research team desires to estimate the populatie The sample mean was 3.15.
can you answer c and also solve for the z value please
n=16 mean number of television per household is 4 with a standard deviation of 1 television. using chebychev's theorem, detemine at least how many households have between 2 and 6 television.
Answer 3 & 4
A normal distribution with a mean of 2mm and a standard deviation of 0.05mm a randomly generated number of 0.71 , need to calculate the standardised Z value, from my notes Z = (actual value - mean)/standard deviation. do i take the randomly generated number of 0.81 as the actual value ?
Help me please
Use the information to make a normal distribution using the Empirical Rule, label the mean and three standard deviations from the mean.
Write the formulae Given a normal distribution with mean of 12 & standard deviation of 2. What is the P (11 ≤ x ≤ 13)?
The Z-score tells you the number of standard deviations away from the mean (and in what direction) a data value is. The formula: Z = *- can be used to find the Z-score for a single member of the population. Notice X - μ tells you the signed distance the data value (X) is from the mean. When you divide that by the size of each chunk (the standard deviation) you are measuring the distance in units of the size of the standard deviations (how many standard deviations fit in the distance between the data value and the mean) - which gives you the Z-score. The formula X = μ+Z.o can be used to find the value in the population when given the Z-score (signed number of standard deviations). Notice that Z. tells you how far from the mean the data value is (since Z is the number of standard deviations and is the size of each standard deviation the product tells the total distance). So adding the distance from the mean to the mean gives the location along the number line for the data value. A…