7. Find AH for the following reaction: C6H12O6 (s) 2 C₂H5OH (l) + 2 CO₂ (g) The standard enthalpies of formation are: 6 C(s) + 6 H₂(g) + 3 O₂(g) → C6H12O6 (s) 2 C(s) + 3 H₂(g) + O2(g) → C₂H5OH (l) C(s) + O2 (g) → CO₂ (g) AH--1273 kJ/mol AH°f=-278 kJ/mol AHf -394 kJ/mol

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7. Find AH for the following reaction:
C6H12O6 (s) 2 C₂H5OH (l) + 2 CO₂ (g)
The standard enthalpies of formation are:
6 C(s) + 6 H₂(g) + 3 O2(g) → C6H12O6 (s)
2 C(s) + 3 H₂(g) + O2(g) → C₂H5OH (l)
C(s) + O₂ (g) → CO₂ (g)
AH =-1273 kJ/mol
AH°f=-278 kJ/mol
AHᵒf -394 kJ/mol
Transcribed Image Text:7. Find AH for the following reaction: C6H12O6 (s) 2 C₂H5OH (l) + 2 CO₂ (g) The standard enthalpies of formation are: 6 C(s) + 6 H₂(g) + 3 O2(g) → C6H12O6 (s) 2 C(s) + 3 H₂(g) + O2(g) → C₂H5OH (l) C(s) + O₂ (g) → CO₂ (g) AH =-1273 kJ/mol AH°f=-278 kJ/mol AHᵒf -394 kJ/mol
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This question is answered by using the simple concept of Hess law of constant heat summation which states that heat change will remain constant whether a reaction takes place in single step or in the number of steps .

 

 

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