7. Considering the following chemical, which statement is true? CHO H-C-OH -C-H HO-C-H H-C-OH CH₂OH A. It needs to form the ring form first before it can interact with methanol to form an intramolecular hemiketal B. When the molecule forms the ring form, the carbon atom #5 becomes the anomeric carbon C. Both A and B D. Neither A nor B
7. Considering the following chemical, which statement is true? CHO H-C-OH -C-H HO-C-H H-C-OH CH₂OH A. It needs to form the ring form first before it can interact with methanol to form an intramolecular hemiketal B. When the molecule forms the ring form, the carbon atom #5 becomes the anomeric carbon C. Both A and B D. Neither A nor B
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter22: Organic And Biological Molecules
Section: Chapter Questions
Problem 176MP
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Transcribed Image Text:### Question 7: Considering the following chemical, which statement is true?
**Diagram Explanation:**
The diagram depicts an open-chain form of a carbohydrate molecule, most likely a glucose molecule. It contains the following structure:
```
CHO
|
H - C - OH
|
HO - C - H
|
HO - C - H
|
H - C - OH
|
CH2OH
```
**Answer Choices:**
A. It needs to form the ring form first before it can interact with methanol to form an intramolecular hemiacetal.
B. When the molecule forms the ring form, the carbon atom #5 becomes the anomeric carbon.
C. Both A and B
D. Neither A nor B
**Detailed Explanation:**
The structure shown is an open-chain form of a monosaccharide. In aqueous solution, this monosaccharide can cyclize to form a ring structure through an intramolecular reaction where the hydroxyl group on one of the carbon atoms (typically the penultimate carbon, in this case, carbon atom #5) reacts with the aldehyde group (located on carbon atom #1). This results in the formation of a hemiacetal.
- **Statement A**: This is true. In the formation of a hemiacetal, the molecule usually has to convert to its cyclic form.
- **Statement B**: This is incorrect. When the ring forms, carbon atom #1 (the carbonyl carbon) becomes the anomeric carbon, not carbon atom #5.
**Correct Answer:**
D. Neither A nor B
This transcription and explanation provide an understanding of monosaccharide behavior in cyclization reactions, relevant to the given chemical structure.
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