7. Consider the molecule below. How many pi (x) bonds are present? HHH H a. 27 b. 13 c. 5 d. 6 8. What would you call the bonding depicted in the two images below? a. I depicts sigma bonding and II depicts pi bonding b. I depicts pi bonding and II depicts sigma bonding c. I and II depict sigma bonding d. I and II depict pi bonding EC-H OH 11 9. Which of the following violates the rules for curved arrows and creates a nonvalid resonance structure? of :0:

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7. Consider the molecule below. How many pi (r) bonds are present?
a. 27
b. 13
8. What would you call the bonding depicted in the two images below?
c. 5
d. 6
a. I depicts sigma bonding and II depicts pi bonding
b. I depicts pi bonding and II depicts sigma bonding
c. I and II depict sigma bonding
d. I and II depict pi bonding
of
I
9. Which of the following violates the rules for curved arrows and creates a nonvalid resonance
structure?
a. one
b. two
c. three
H
10. Which element has the electron configuration 1s² 2s²2p³?
a. O
c. S
d. Cl
b. F
✪
H
11. How many hydrogen atoms are connected to the indicated carbon atom?
H
d. four
e. none
a. CH3C(CH3)₂CH₂CH₂(CH)BrC(CH3)2
b. CH3CH3CH3CCH₂CH₂C(CH3)2CHBr
c. (CH3)3CCH₂CH₂CH₂BrCHCH3CH3
12. Which of the following is the correct condensed structure for the following compound?
OH
HH H
HH
с
2
||
↓ d d
H Br H H
d
H
d. CH₂CH₂CH₂CCH₂CH₂CHBrCHCH₂CH₂
e. (CH3)3CCH₂CH₂CHBRCH(CH3)2
Transcribed Image Text:7. Consider the molecule below. How many pi (r) bonds are present? a. 27 b. 13 8. What would you call the bonding depicted in the two images below? c. 5 d. 6 a. I depicts sigma bonding and II depicts pi bonding b. I depicts pi bonding and II depicts sigma bonding c. I and II depict sigma bonding d. I and II depict pi bonding of I 9. Which of the following violates the rules for curved arrows and creates a nonvalid resonance structure? a. one b. two c. three H 10. Which element has the electron configuration 1s² 2s²2p³? a. O c. S d. Cl b. F ✪ H 11. How many hydrogen atoms are connected to the indicated carbon atom? H d. four e. none a. CH3C(CH3)₂CH₂CH₂(CH)BrC(CH3)2 b. CH3CH3CH3CCH₂CH₂C(CH3)2CHBr c. (CH3)3CCH₂CH₂CH₂BrCHCH3CH3 12. Which of the following is the correct condensed structure for the following compound? OH HH H HH с 2 || ↓ d d H Br H H d H d. CH₂CH₂CH₂CCH₂CH₂CHBrCHCH₂CH₂ e. (CH3)3CCH₂CH₂CHBRCH(CH3)2
Expert Solution
Step 1

#7:

π-bonds are formed due to sideways overlapping of hybrid orbitals. 

A single bond has 1 sigma bond and no π-bond. 

A double bond has 1 sigma bond and 1π-bond.

A triple bond has 1 sigma bond and 2π-bonds.

 

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