7. An old "trick" for cooling down a hot beverage quickly is to immerse a cold spoon into the liquid. A silver spoon weighing 3.20 oz and at a temperature of 20°C is placed in a cup of hot coffee (8.00 oz) at 70°C. What will be the resulting liquid temperature? Assume that specific heat of coffee is 4.18 J g-1 °C-1 and that of silver is 0.234 J g-1 °C-1. Comment on the effectiveness of this method of cooling a hot drink. 1 g = 0.0352 oz

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem 7: Cooling a Hot Beverage with a Cold Spoon**

**Introduction:**
An old "trick" for cooling down a hot beverage quickly is to immerse a cold spoon into the liquid. Let's analyze the effectiveness of this method using the example below:

**Problem Statement:**

- A silver spoon weighing 3.20 oz at a temperature of 20°C is placed in a cup of hot coffee (8.00 oz) at 70°C.
- Determine the resulting liquid temperature after the interaction.
  
**Given:**

- Specific heat of coffee: 4.18 J g⁻¹ °C⁻¹
- Specific heat of silver: 0.234 J g⁻¹ °C⁻¹
- Conversion factor: 1 g = 0.0352 oz

**Questions:**
1. What will be the resulting liquid temperature?
2. Comment on the effectiveness of this cooling method.

This problem involves applying principles of heat transfer to determine how effective immersing a cold spoon is for cooling a hot drink.
Transcribed Image Text:**Problem 7: Cooling a Hot Beverage with a Cold Spoon** **Introduction:** An old "trick" for cooling down a hot beverage quickly is to immerse a cold spoon into the liquid. Let's analyze the effectiveness of this method using the example below: **Problem Statement:** - A silver spoon weighing 3.20 oz at a temperature of 20°C is placed in a cup of hot coffee (8.00 oz) at 70°C. - Determine the resulting liquid temperature after the interaction. **Given:** - Specific heat of coffee: 4.18 J g⁻¹ °C⁻¹ - Specific heat of silver: 0.234 J g⁻¹ °C⁻¹ - Conversion factor: 1 g = 0.0352 oz **Questions:** 1. What will be the resulting liquid temperature? 2. Comment on the effectiveness of this cooling method. This problem involves applying principles of heat transfer to determine how effective immersing a cold spoon is for cooling a hot drink.
Expert Solution
Step 1

Since the hot coffee is at a higher temperature, it releases heat and the silver spoon accepts heat released by the coffee. 

Suppose the resulting liquid temperature is "T" o

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