7. A1,200 kg car accelerates from rest to 27 m/s in 6 seconds. How much power does the engine exert on the car during this acceleration? m= 1200kg Vi = Om/s F=(1200YA.5) F= 5,400N F=ma Vf =Vi +(a)X+) 27=0+a(ašec) %3D Vf- 27m/s Pawere FV t=6sec 6a= 27 (5,400X27.0m/s)
7. A1,200 kg car accelerates from rest to 27 m/s in 6 seconds. How much power does the engine exert on the car during this acceleration? m= 1200kg Vi = Om/s F=(1200YA.5) F= 5,400N F=ma Vf =Vi +(a)X+) 27=0+a(ašec) %3D Vf- 27m/s Pawere FV t=6sec 6a= 27 (5,400X27.0m/s)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Number 8 I need help on.

Transcribed Image Text:7. A1,200 kg car accelerates from rest to 27 m/s in 6 seconds. How much power does the engine exert on the
car during this acceleration?
m= 1200kg
Vi= Om/s
F= ma
Vf = Vi+(a)(+)
27=0+a(ašec)
F= (1200YA.5)
F= 5,400N
%3D
Vf- 27m/s
Pawere FN
(5,400X27.0m/5)
コ15,800W)1935型
t=6sec
4.5 m/s2
8. A 400 hp engine in a 1,600 kg car applies maximum force for 2 seconds to accelerate the car onto the
HP
interstate. If the car moves at 8 m/s before accelerating, what is its speed after the 2 seconds of acceleration?
- 4Cohp engine
- loco0 kg
Unit 4i_Practice Problems
Copyright © 2018 Georgia Public Broadcasting. All rights reserved. Use or distribution by an unintended recipient is prohibited.
Power= FV ( force velocit)
veleo
%3D
Examples
1006,0k9 car
m=1008.0K9
accelerates O m/s 27,0 m/6
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