A student places 0.272 mol of PC13(g) and 8.56 x 10-4 mol of PC15(g) into a 0.718-L flask ata certain temperature. PCI5(g) is known to dissociate as follows:7.PCI5(g) > PC13(g)| + Cl2(g)After the reaction attains equilibrium, the student finds that the flask contains 2.51 x 10-4 mol ofClg). Calculate the equilibrium constant, Kc, for the reaction at this temperature.

Answered: Image /qna-images/answer/4350dadc-46ab-4cb2-a9a2-54d536b1cbf7.jpg

7. A student places 0.272 mol of PC13(g) and 8.56 x 10-4 mol of PC15(2) into a 0.718-L flask at a certain temperature. PCI5(g) is known to dissociate as follows: PC15(g) +→ PC13(g)| + Cl2(g) After the reaction attains equilibrium, the student finds that the flask contains 2.51 x 10-4 mol of Cl(g). Calculate the equilibrium constant, Kc, for the reaction at this temperature.

7. A student places 0.272 mol of PC13(g) and 8.56 x 10-4 mol of PC15(2) into a 0.718-L flask at a certain temperature. PCI5(g) is known to dissociate as follows: PC15(g) +→ PC13(g)| + Cl2(g) After the reaction attains equilibrium, the student finds that the flask contains 2.51 x 10-4 mol of Cl(g). Calculate the equilibrium constant, Kc, for the reaction at this temperature.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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