7. A CDMA receiver gets the following chips: (-1 +1 -3 +1 -1 -3 +1+1). Assuming the chip sequences for stations A, B, C, and D are defined as the following, A = (-1 -1 -1+1 +1 -1+1+1) B=(-1 -1+1 -1+1+1+1 -1) C= (-1+1 -1 +1 +1+1 -1 -1) D= (-1+1 -1 -1 -1 -1 +1 -1) Which stations transmitted, and which bits did each one send?

7. A CDMA receiver gets the following chips: (-1 +1 -3 +1 -1 -3 +1+1). Assuming the chip sequences for stations A, B, C, and D are defined as the following, A = (-1 -1 -1+1 +1 -1+1+1) B=(-1 -1+1 -1+1+1+1 -1) C= (-1+1 -1 +1 +1+1 -1 -1) D= (-1+1 -1 -1 -1 -1 +1 -1) Which stations transmitted, and which bits did each one send?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

An unmodulated carrier is 680 Vp-p. Calculate the %m when its maximum p-p value reaches 650, 850 and 1050 V, and the minimum p-p value reaches 500, 300 and 50 V, respectively, upon modulation.
2. Find the resules for each of dhe followiag: 1. (1011); + (101); 2. (166), + (342 )s 3. (A91he + (24De 4. (10111), - (11001), using 25 complement. 5. (563)s - (271) using 8'5 complement, 6. (C92ha - (A3Bhs using 16'S complemeat. 7. (0101); + (0100); in BCD. S. (1000): + (1001): in BCD. 9. (101):" (0110):
Limiter circuits are used for clipping the amplitude of the carrier signals in FM transmissions. True False
Calculate the propagation delay and RTT for a 100 m copper link.
Derive the expression for Zin
If the voltage of the carrier(Voc) is greater than from the Voltage message (Vm). Therefore the value of the modulation index (m) would be, (a) greater than 1 (b) less than 1 (c) equal to 1 (d) infinty For ZR #Z0, the total reflection is occurred when the load is short circuit. the value of the voltage and the current Exets Ixts (a) Ext=max, 1x=1 = 0 (b) Exal = 0, Ixal = max (c) Exet=max, Ixt = max (d) Ext=0, Ixt = 0 The electrical distance (as a function of the wavelength) between two successive minimum voltages in the standing wave pattern of a TL is equal to (a) 0.2 (b) 0.25 (c) 0.5 (d) 0.75 The highest power efficiency can be achieved in the conventional DSB-AM modulation (b) 33% (a) 23% (c) 53% (d) 73%
Question 3 Figure below shows how a single wire can be used to carry measurement data at the same time. This is done by modulating two widely different carrier frequencies with data and using filters to extract the data at the receiving end. Suppose one data channel is a modulated signal of 1.0 to 1.5 kHz and the other is a modulated signal of 50 to 55 kHz. Design the extraction filters using simple RC filters such that the data loss is restricted to 0.707 (3 dB, or 50% power) in the data signals. How much amplitude crossover results? (What is the amplitude ratio of the 50-55 kHz in the 1-1.5-kHz channel and vice versa?) Signal 1 50-kHz Modulator oscillator Filter1 Demodulator Signal 1 23-11 Adder Transmission 1-kHz Modulator Filter2 oscillator Demodulator Signal 2 Signal 2
State and explain with diagram and reasons how the GaN LNA Receiver design can be modified with Network Traps to avoid bits of signal power loss and removing undesired harmonics of radiated signals in the Transceiver of figure 1 which finds use in several Giga Hertz Frequency for wireless communication applications.
How could I get the thevnin voltage from this using the transfer funciton and the lookback method?
Don't need to elaborate the answer. Just write down the correct answer. Some questions may have multiple answers. 1) Which multiplexing technique shifts each signal to a different carrier frequency? a) FDM b) TDM c) WDM d) PDM 2) Which multiplexing technique involves signals composed of light beams? a) FDM b) TDM c) WDM d) PDM 3) We need an addressing mechanism in a) Satic b) Parallel c) Synchronous d) Statistical 4) Pulse stuffing is a strategy used in a) TDM b) FDM c) FHSS d) WDM 5) a) FDM b) TDM technique uses multiple carrier frequencies. c) WDM d) FHSS e) DSSS TDM. 6) We need to use synchronous TDM and combine 20 digital sources, each of 100 Kbps. Each output slot carries 1 bit from each digital source, but one extra bit is added to each frame for synchronization. Answer the following questions: i) What is the size of an output frame in bits? a) 10 b) 20 c) 21 d) 11 ii) What is the output frame rate? a) 200000 frames/sec b) 210000 frames/sec c) 10000 frames/sec d) 100000…
l need the answer in 30 mints please please please.
The different access methods which permit many satellite users to operate in parallel through a single transponder without interfering with each other are 1. Frequency Division Multiple Access (FDMA) 2. Time Division Multiple Access (TDMA) 3. Code Division Multiple Access (CDMA) Which of the above are correct?