7. A baseball bat exerts an average force of 600. newtons east on a ball, imparting an impulse of 3.6 newton-seconds east to the ball. (a)Calculate the amount of time the baseball bat is in contact with the ball. (b) If the incoming baseball has a mass of 0.2 kg and an incoming speed of 10 m/s, find how much is the change of momentum magnitude after it was hit by the bat? how much is the new speed of the baseball after it was hit by the bat?/V CO 50 or gecond on a horizontal
7. A baseball bat exerts an average force of 600. newtons east on a ball, imparting an impulse of 3.6 newton-seconds east to the ball. (a)Calculate the amount of time the baseball bat is in contact with the ball. (b) If the incoming baseball has a mass of 0.2 kg and an incoming speed of 10 m/s, find how much is the change of momentum magnitude after it was hit by the bat? how much is the new speed of the baseball after it was hit by the bat?/V CO 50 or gecond on a horizontal
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Conservation of Momentum \( P = P' \)
#### Problems:
7.
A baseball bat exerts an average force of 600 newtons east on a ball, imparting an impulse of 3.6 newton-seconds east to the ball.
(a) Calculate the amount of time the baseball bat is in contact with the ball.
(b) If the incoming baseball has a mass of 0.2 kg and an incoming speed of 10 m/s, find how much is the change of momentum magnitude after it was hit by the bat? How much is the new speed of the baseball after it was hit by the bat?
8.
When a 1.0-kilogram cart moving with a speed of 0.50 meter per second on a horizontal surface collides with a second 1.0-kilogram cart initially at rest, the carts lock together. What is the speed of the combined carts after the collision?
### IV. Work, Power and Energy
**Work \( W = Fd \) = (force) (displacement), Power = work/time = \( F(V) = F(V) = (force)(velocity) \)**
**Work-Energy Theorem:**
\[ work = \Delta E = PE + KE + Thermal energy + internal energy, etc. \]
**That means work done on a system will cause the energy change (increase).**
9.
Two elevators, A and B, move at constant speed. Elevator B moves with twice the speed of elevator A. Elevator B weighs twice as much as elevator A. Compared to the power needed to lift elevator A, the power needed to lift elevator B is:
(1) the same (3) half as great (2) twice as great (4) four times as great
10.
What is the maximum height to which a motor having a power rating of 20.4 watts can lift a 5.00-kilogram stone vertically in 10.0 seconds?
11.
A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters.
The following image is a diagram:
```
-------
/ \
/ \
/ \
/ \
/ \
/ \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc4175da-4ff6-4fd6-a490-92fdbc76bb02%2F4f93590c-3544-4e97-b972-e861be4af181%2Fpp0y67g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Conservation of Momentum \( P = P' \)
#### Problems:
7.
A baseball bat exerts an average force of 600 newtons east on a ball, imparting an impulse of 3.6 newton-seconds east to the ball.
(a) Calculate the amount of time the baseball bat is in contact with the ball.
(b) If the incoming baseball has a mass of 0.2 kg and an incoming speed of 10 m/s, find how much is the change of momentum magnitude after it was hit by the bat? How much is the new speed of the baseball after it was hit by the bat?
8.
When a 1.0-kilogram cart moving with a speed of 0.50 meter per second on a horizontal surface collides with a second 1.0-kilogram cart initially at rest, the carts lock together. What is the speed of the combined carts after the collision?
### IV. Work, Power and Energy
**Work \( W = Fd \) = (force) (displacement), Power = work/time = \( F(V) = F(V) = (force)(velocity) \)**
**Work-Energy Theorem:**
\[ work = \Delta E = PE + KE + Thermal energy + internal energy, etc. \]
**That means work done on a system will cause the energy change (increase).**
9.
Two elevators, A and B, move at constant speed. Elevator B moves with twice the speed of elevator A. Elevator B weighs twice as much as elevator A. Compared to the power needed to lift elevator A, the power needed to lift elevator B is:
(1) the same (3) half as great (2) twice as great (4) four times as great
10.
What is the maximum height to which a motor having a power rating of 20.4 watts can lift a 5.00-kilogram stone vertically in 10.0 seconds?
11.
A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters.
The following image is a diagram:
```
-------
/ \
/ \
/ \
/ \
/ \
/ \
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