How can i solve this? **Title: Ballistic Pendulum Analysis for Projectile Speed Measurement****Problem Statement:**A ballistic pendulum is used to measure the speed of bullets or other high-speed projectiles. In this scenario, an 8 g bullet is fired into a 1 kg wood block suspended by a cord with a length of \( l = 2.0 \, m \). The block swings through a maximum angle of \( \theta = 60^\circ \).**Objectives:**Determine:a) The initial speed of the bullet prior to collision.b) The impulse imparted by the bullet on the block.**Diagram Explanation:**The illustration depicts a ballistic pendulum setup:- The wood block (labeled B) is attached to a cord and is initially at rest.- After the bullet embeds into the block, the combined mass swings, creating an angle of \( \theta \) with the vertical.- The pendulum effect allows the calculation of energy and momentum changes due to the collision, assisting in determining the speed and impulse.This setup effectively translates linear motion into angular displacement, providing insights into projectile dynamics through conservation of momentum and energy principles.

Given data: Mass of bullet is m = 8 g×1 kg1000 g=0.008 kg. Mass of block is M = 1 kg. Length of cord is l = 2 m. Angle subtended θ=60°. Applying conservation of momentum between the bullet and block, mv0=m+Mvv0=m+Mvm.......(1) Here, v is the velocity of bullet just after impact. Applying conservation of energy between two position of block, KE=PE12m+Mv2=m+Mgh12v2=ghv=2gh......(2) Here, h is the vertical distance and g is the gravitation acceleration.Vertical distance can be calculated as, h=l-lcosθh=2 m-2 m×cos60°h=2 m-2 m×cos60°h=1 m Substitute in equation (2), v=2ghv=2×9.81 m/s2×1 m v=4.43 m/s Part (a) The initial speed of bullet can be calculated by substituting all the values in equation (1), v0=m+Mvmv0=0.008 kg+1 kg4.43 m/s0.008 kgv0=558.18 m/s Thus, the initial velocity is 558.18 m/s. Part (b) Impulse imparted by the bullet on block is, p=mv0p=0.008 kg×558.18 m/sp=4.465 kg·m/s Thus, the impulse is 4.465 m/s.