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7) Water is flowing upward at 1.676 m/s through a vertical piping system consisting of 3" sch40 steel pipe at the inlet and 2" sch40 steel pipe at the outlet. The vertical distance from the inlet to the outlet is 0.457 m. The inlet pressure is 68.9 kPa absolute. Assuming no friction losses, what will be the outlet pressure?

7) Water is flowing upward at 1.676 m/s through a vertical piping system consisting of 3" sch40 steel pipe at the inlet and 2" sch40 steel pipe at the outlet. The vertical distance from the inlet to the outlet is 0.457 m. The inlet pressure is 68.9 kPa absolute. Assuming no friction losses, what will be the outlet pressure?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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INSTRUCTIONS: Solve theproblems neatly and systematically. Use free-floating decimals in all your calculations and in expressing your answers. Box your final answers

 

KINDLY FOLLOW THIS FORMAT GIVE,REQUIRED,SOLUTION

 

ADDITIONAL: USE THE OTHER PICTURE AS BASIS FORMULA IF NEEDED IN YOUR SOLUTION THANK YOU

PRESSURE RECOVERY: Because of the large friction losses from the eddies generated by the reexpanding jet below the vena contracta, the pressure in an orifice meter is poor. The resulting power loss is one disadvantage of the orifice meter. The fraction of the orifice differential that is permanently lost depends on the value of B (refer to figure 8.19). Power requirement for an orifice = fraction of orifice differential lost x ( Pa – Pb ) x volumetric flowrate DEVELOPED HEAD: Bernoulli Equation: (P2 , azV? + z2 2gc - ) P a,V? + z1° 2gc Npump Wpump = (2 gc gc The quantities in parenthesis are called TOTAL HEADS and are denoted by H. Therefore: W, H-Ha ΔΗ POWER REQUIREMENT: PB = m Wp = m AH EDIFICA Pr %3D where: Pa, Pb = pressure at the suction and discharge lines V = velocity H = total head Ps = the power supplied to the pump Z = height above the datum plane P: = the power delivered to the fluid
Transcribed Image Text:PRESSURE RECOVERY: Because of the large friction losses from the eddies generated by the reexpanding jet below the vena contracta, the pressure in an orifice meter is poor. The resulting power loss is one disadvantage of the orifice meter. The fraction of the orifice differential that is permanently lost depends on the value of B (refer to figure 8.19). Power requirement for an orifice = fraction of orifice differential lost x ( Pa – Pb ) x volumetric flowrate DEVELOPED HEAD: Bernoulli Equation: (P2 , azV? + z2 2gc - ) P a,V? + z1° 2gc Npump Wpump = (2 gc gc The quantities in parenthesis are called TOTAL HEADS and are denoted by H. Therefore: W, H-Ha ΔΗ POWER REQUIREMENT: PB = m Wp = m AH EDIFICA Pr %3D where: Pa, Pb = pressure at the suction and discharge lines V = velocity H = total head Ps = the power supplied to the pump Z = height above the datum plane P: = the power delivered to the fluid
7) Water is flowing upward at 1.676 m/s through a vertical piping system consisting of 3" sch40 steel pipe at the inlet and 2" sch40 steel pipe at the outlet. The vertical distance from the inlet to the outlet is 0.457 m. The inlet pressure is 68.9 kPa absolute. Assuming no friction losses, what will be the outlet pressure?
Transcribed Image Text:7) Water is flowing upward at 1.676 m/s through a vertical piping system consisting of 3" sch40 steel pipe at the inlet and 2" sch40 steel pipe at the outlet. The vertical distance from the inlet to the outlet is 0.457 m. The inlet pressure is 68.9 kPa absolute. Assuming no friction losses, what will be the outlet pressure?
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