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7- The region in which 4 < r < 5,0 <0 < 25°, and 0.9x < < 1.17 contains the volume charge density of p, 10(-4) (r-5) sin 0 sin(p/2). Outside the region, P, = 0. Find the charge within the region: The integral that gives the charge will be = 1.1x 25° Q=10 - 10 fotott fotosh ( ² (r-4) (r-5) sin 0 sin(0/2) r² sine dr de do 9x 10+20][20-sin(20)][-200 (9) =10(-3.39) (.0266)(.626)=0.57 C

7- The region in which 4 < r < 5,0 <0 < 25°, and 0.9x < < 1.17 contains the volume charge density of p, 10(-4) (r-5) sin 0 sin(p/2). Outside the region, P, = 0. Find the charge within the region: The integral that gives the charge will be = 1.1x 25° Q=10 - 10 fotott fotosh ( ² (r-4) (r-5) sin 0 sin(0/2) r² sine dr de do 9x 10+20][20-sin(20)][-200 (9) =10(-3.39) (.0266)(.626)=0.57 C

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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electromagnetic field)I want a detailed solution because my teacher changes the numbers. I want a detailed solution. Understand the solution
7- The region in which 4 < r < 5,0 <0 < 25°, and 0.9x << 1.17 contains the volume charge density of p, 10(-4) (r-5) sin 0 sin(4/2). Outside the region, P, = 0. Find the charge within the region: The integral that gives the charge will be = 1.1x [²² ²²- (r-4) (r-5) sin 0 sin(6/2) r² sin 0 dr de do 9x Q=10 0-10-20-02) [-200 (9) cos 9x =10(-3.39) (.0266) (.626)=0.57 C sin
Transcribed Image Text:7- The region in which 4 < r < 5,0 <0 < 25°, and 0.9x << 1.17 contains the volume charge density of p, 10(-4) (r-5) sin 0 sin(4/2). Outside the region, P, = 0. Find the charge within the region: The integral that gives the charge will be = 1.1x [²² ²²- (r-4) (r-5) sin 0 sin(6/2) r² sin 0 dr de do 9x Q=10 0-10-20-02) [-200 (9) cos 9x =10(-3.39) (.0266) (.626)=0.57 C sin
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