7) The reaction: A + B = 2 C, can be represented by the equilibrium expression, Kc = [C]² =258 at 520K. [A][B] When 1.00 M of C was allowed to reach equilibrium and 0.062 M of A was formed. If this reaction was performed at the same temperature using 0.500 M C, what would the equilibrium concentration of A be?
7) The reaction: A + B = 2 C, can be represented by the equilibrium expression, Kc = [C]² =258 at 520K. [A][B] When 1.00 M of C was allowed to reach equilibrium and 0.062 M of A was formed. If this reaction was performed at the same temperature using 0.500 M C, what would the equilibrium concentration of A be?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![7) The reaction: A + B = 2 C, can be represented by the equilibrium expression, Kc = [c]²
[A][B]
When 1.00 M of C was allowed to reach equilibrium and 0.062 M of A was formed. If this reaction was
performed at the same temperature using 0.500 M C, what would the equilibrium concentration of A
be?
= 258 at 520K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Febada570-e7a6-4ba9-97bf-6b504d7c9a31%2Fe270f3dc-fae9-4316-a16e-3ca0996a9458%2F43s6v_processed.png&w=3840&q=75)
Transcribed Image Text:7) The reaction: A + B = 2 C, can be represented by the equilibrium expression, Kc = [c]²
[A][B]
When 1.00 M of C was allowed to reach equilibrium and 0.062 M of A was formed. If this reaction was
performed at the same temperature using 0.500 M C, what would the equilibrium concentration of A
be?
= 258 at 520K.
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