G-h. Thank you in advance 7|The position vs time plot for the tip of the beakof a woodpecker is shown to the right (→). You|can assume that the acceleration is nearly|constant for the first two milliseconds. A coupleof points are also given in the table below. Awoodpecker head has a mass of about 10g.43-1.46 810 12 14 16 18 20 22 24time (ms)-1r(t = 1ms)-1mm-2-2m/sa. Determine the position at t = 0.v(t = 0)b. Determine the position at t = 2ms.c. Calculate the acceleration of the during this time.d. Find an equation for the position as a function of time for the first two milliseconds.e. Calculate the force on the woodpecker head during the first two milliseconds.f. Find an equation for the velocity as a function of time for the first two milliseconds.g. Calculate the velocity of the object at t = 2ms.h. Carefully plot the velocity, and acceleration versus time of the woodpecker head forthe first two milliseconds. OANSWERS1 a. tf1.27s; b. řf = -6.60mj, tf = 4.00s; c. V; = –3.50mj, ā =%3D2 half as much3 they are all the same4| car5|a. 0.379m/s²-; b. 0.535m/s²÷; c. 4.17m/s²6 a. 9.8m/s²1; b. 54.2m/s; c. 5.53s; d. 11.1m;7 c. 2mm/ms?; d. (-2mm/ms)t + (1mm/ms²)ť²; e. 20.0N; f. (-2mm/ms) + (2mm/ms²)t; g.2mm/ms;8 a. 3.35m/s²; b. 275N;

7 The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You |can assume that the acceleration is nearly constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 3- 6 8 10 12 14 16 18 20 22 24 time (ms) r(t = 1ms) -1mm 4. 4. 2. 1. position (mm)

7 The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You |can assume that the acceleration is nearly constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 3- 6 8 10 12 14 16 18 20 22 24 time (ms) r(t = 1ms) -1mm 4. 4. 2. 1. position (mm)