7 The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You can assume that the acceleration is nearly constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 3 8 10 12 14 16 18 20 22 24 time (ms) 4 6 -1 r(t = 1ms) -1mm -2m/s a. Determine the position at t = 0. v(t = 0) b. Determine the position at t = 2ms. c. Calculate the acceleration of the during this time. d. Find an equation for the position as a function of time for the first two milliseconds. e. Calculate the force on the woodpecker head during the first two milliseconds. f. Find an equation for the velocity as a function of time for the first two milliseconds. g. Calculate the velocity of the object at t = 2ms. h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for the first two milliseconds. (uu) uorzsod
7 The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You can assume that the acceleration is nearly constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 3 8 10 12 14 16 18 20 22 24 time (ms) 4 6 -1 r(t = 1ms) -1mm -2m/s a. Determine the position at t = 0. v(t = 0) b. Determine the position at t = 2ms. c. Calculate the acceleration of the during this time. d. Find an equation for the position as a function of time for the first two milliseconds. e. Calculate the force on the woodpecker head during the first two milliseconds. f. Find an equation for the velocity as a function of time for the first two milliseconds. g. Calculate the velocity of the object at t = 2ms. h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for the first two milliseconds. (uu) uorzsod
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D-f. Thank you in advance
Transcribed Image Text:7|The position vs time plot for the tip of the beak
of a woodpecker is shown to the right (→). You
|can assume that the acceleration is nearly
|constant for the first two milliseconds. A couple
of points are also given in the table below. A
woodpecker head has a mass of about 10g.
4
3-
1.
4
6 8
10 12 14 16 18 20 22 24
time (ms)
-1
r(t = 1ms)
-1mm
-2
-2m/s
a. Determine the position at t = 0.
v(t = 0)
b. Determine the position at t = 2ms.
c. Calculate the acceleration of the during this time.
d. Find an equation for the position as a function of time for the first two milliseconds.
e. Calculate the force on the woodpecker head during the first two milliseconds.
f. Find an equation for the velocity as a function of time for the first two milliseconds.
g. Calculate the velocity of the object at t = 2ms.
h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for
the first two milliseconds.
Transcribed Image Text:OANSWERS
1 a. tf
1.27s; b. řf = -6.60mj, tf = 4.00s; c. V; = –3.50mj, ā =
%3D
2 half as much
3 they are all the same
4| car
5|a. 0.379m/s²-; b. 0.535m/s²÷; c. 4.17m/s²
6 a. 9.8m/s²1; b. 54.2m/s; c. 5.53s; d. 11.1m;
7 c. 2mm/ms?; d. (-2mm/ms)t + (1mm/ms²)ť²; e. 20.0N; f. (-2mm/ms) + (2mm/ms²)t; g.
2mm/ms;
8 a. 3.35m/s²; b. 275N;
Expert Solution
Step 1
Given:
The mass of the woodpecker head is .
The acceleration for the first two milliseconds is constant and it is .
The position of the tip at is .
The velocity at time is .
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