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7 The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You can assume that the acceleration is nearly constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 3 8 10 12 14 16 18 20 22 24 time (ms) 4 6 -1 r(t = 1ms) -1mm -2m/s a. Determine the position at t = 0. v(t = 0) b. Determine the position at t = 2ms. c. Calculate the acceleration of the during this time. d. Find an equation for the position as a function of time for the first two milliseconds. e. Calculate the force on the woodpecker head during the first two milliseconds. f. Find an equation for the velocity as a function of time for the first two milliseconds. g. Calculate the velocity of the object at t = 2ms. h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for the first two milliseconds. (uu) uorzsod

7 The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You can assume that the acceleration is nearly constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 3 8 10 12 14 16 18 20 22 24 time (ms) 4 6 -1 r(t = 1ms) -1mm -2m/s a. Determine the position at t = 0. v(t = 0) b. Determine the position at t = 2ms. c. Calculate the acceleration of the during this time. d. Find an equation for the position as a function of time for the first two milliseconds. e. Calculate the force on the woodpecker head during the first two milliseconds. f. Find an equation for the velocity as a function of time for the first two milliseconds. g. Calculate the velocity of the object at t = 2ms. h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for the first two milliseconds. (uu) uorzsod

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7|The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You |can assume that the acceleration is nearly |constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 4 3- 1. 4 6 8 10 12 14 16 18 20 22 24 time (ms) -1 r(t = 1ms) -1mm -2 -2m/s a. Determine the position at t = 0. v(t = 0) b. Determine the position at t = 2ms. c. Calculate the acceleration of the during this time. d. Find an equation for the position as a function of time for the first two milliseconds. e. Calculate the force on the woodpecker head during the first two milliseconds. f. Find an equation for the velocity as a function of time for the first two milliseconds. g. Calculate the velocity of the object at t = 2ms. h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for the first two milliseconds.
Transcribed Image Text:7|The position vs time plot for the tip of the beak of a woodpecker is shown to the right (→). You |can assume that the acceleration is nearly |constant for the first two milliseconds. A couple of points are also given in the table below. A woodpecker head has a mass of about 10g. 4 3- 1. 4 6 8 10 12 14 16 18 20 22 24 time (ms) -1 r(t = 1ms) -1mm -2 -2m/s a. Determine the position at t = 0. v(t = 0) b. Determine the position at t = 2ms. c. Calculate the acceleration of the during this time. d. Find an equation for the position as a function of time for the first two milliseconds. e. Calculate the force on the woodpecker head during the first two milliseconds. f. Find an equation for the velocity as a function of time for the first two milliseconds. g. Calculate the velocity of the object at t = 2ms. h. Carefully plot the velocity, and acceleration versus time of the woodpecker head for the first two milliseconds.
OANSWERS 1 a. tf 1.27s; b. řf = -6.60mj, tf = 4.00s; c. V; = –3.50mj, ā = %3D 2 half as much 3 they are all the same 4| car 5|a. 0.379m/s²-; b. 0.535m/s²÷; c. 4.17m/s² 6 a. 9.8m/s²1; b. 54.2m/s; c. 5.53s; d. 11.1m; 7 c. 2mm/ms?; d. (-2mm/ms)t + (1mm/ms²)ť²; e. 20.0N; f. (-2mm/ms) + (2mm/ms²)t; g. 2mm/ms; 8 a. 3.35m/s²; b. 275N;
Transcribed Image Text:OANSWERS 1 a. tf 1.27s; b. řf = -6.60mj, tf = 4.00s; c. V; = –3.50mj, ā = %3D 2 half as much 3 they are all the same 4| car 5|a. 0.379m/s²-; b. 0.535m/s²÷; c. 4.17m/s² 6 a. 9.8m/s²1; b. 54.2m/s; c. 5.53s; d. 11.1m; 7 c. 2mm/ms?; d. (-2mm/ms)t + (1mm/ms²)ť²; e. 20.0N; f. (-2mm/ms) + (2mm/ms²)t; g. 2mm/ms; 8 a. 3.35m/s²; b. 275N;
Expert Solution
Step 1

Given:

The mass of the woodpecker head is m=10 g.

The acceleration for the first two milliseconds is constant and it is a=2 mmms2.

The position of the tip at t=1 ms is r→=- 1 mm.

The velocity at time t=0 ms is v→=- 2 mmms.

 

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