7 - segment dis pley digital Cincuit :- Truuth table Numben on A Displey A e 1 1 3 4 5 1. Booleam exporesspons for all segments :- Fon 'b' Fon :- BC BC 13 C A 1/ A A A a= Aē + AC+B b = BT +BC +Ā c = B+c+ A Fon 'd For é For f EC BC BE BC BC A A e = Ā ē +B f = BT + A 6 + AT for a ongen's law BC (on) ARC 9 = ABt ĀB+ AĈ A +13+e Legic cincuit Let expressien a = Â +AC+B = 23 MAND gales - Henee heore total minimum 6 NAD gates aro svequi rud. A I NA ND gate U + U O e +

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Please, help with DeMogarn's Theorem to Manipulate at Least One of the Logic Expressions. Thank you.

**Use DeMorgan’s Theorem to Manipulate at Least One of the Logic Expressions**

Now you are going to begin mapping the logic expressions into the logic gates in your parts kit. As you go through this process, you will quickly realize that you do not have enough AND gates and OR gates to implement all seven logic expressions in their derived SOP/POS forms. You will need to manipulate some (or all) of your logic expressions using DeMorgan’s Theorem into forms that use NAND gates and NOR gates. Your lab kits *does* contain a variety of n-input NAND/NOR gates that will allow you to complete the implementation. For this deliverable, show your use of DeMorgan’s to manipulate at least one of your logic expressions from above. Record your logic manipulation electronically.
Transcribed Image Text:**Use DeMorgan’s Theorem to Manipulate at Least One of the Logic Expressions** Now you are going to begin mapping the logic expressions into the logic gates in your parts kit. As you go through this process, you will quickly realize that you do not have enough AND gates and OR gates to implement all seven logic expressions in their derived SOP/POS forms. You will need to manipulate some (or all) of your logic expressions using DeMorgan’s Theorem into forms that use NAND gates and NOR gates. Your lab kits *does* contain a variety of n-input NAND/NOR gates that will allow you to complete the implementation. For this deliverable, show your use of DeMorgan’s to manipulate at least one of your logic expressions from above. Record your logic manipulation electronically.
**7-Segment Display Digital Circuit**

This educational resource provides detailed information about the design and logic of a 7-segment display digital circuit. The document includes a schematic, a truth table, Boolean expressions for each segment, Karnaugh maps, and a logic circuit visualization.

### Schematic Diagram
A 7-segment display consists of seven LEDs labeled as segments a through g. Each segment can be independently lit to display numerals from 0 to 9. Inputs are labeled A, B, and C, and outputs correspond to each segment.

### Truth Table
The truth table maps the combination of inputs (A, B, C) to the segments that need to be active (a, b, c, d, e, f, g) for numerals 0 through 7.

\[
\begin{array}{ccccccccccc}
A & B & C & a & b & c & d & e & f & g & \text{Number Display} \\
0 & 0 & 0 & 1 & 1 & 1 & 1 & 1 & 1 & 0 & 0 \\
0 & 0 & 1 & 0 & 1 & 1 & 0 & 0 & 0 & 0 & 1 \\
0 & 1 & 0 & 1 & 1 & 0 & 1 & 1 & 0 & 1 & 2 \\
0 & 1 & 1 & 1 & 1 & 1 & 1 & 0 & 0 & 1 & 3 \\
1 & 0 & 0 & 0 & 1 & 1 & 0 & 0 & 1 & 1 & 4 \\
1 & 0 & 1 & 1 & 0 & 1 & 1 & 0 & 1 & 1 & 5 \\
1 & 1 & 0 & 1 & 0 & 1 & 1 & 1 & 1 & 1 & 6 \\
1 & 1 & 1 & 1 & 1 & 1 & 0 & 0 & 0 & 0 & 7 \\
\end{array}
\]

### Boolean Expressions for All Segments
Each segment has a unique Boolean expression derived from the Karnaugh maps:

- **Segment a:** \(
Transcribed Image Text:**7-Segment Display Digital Circuit** This educational resource provides detailed information about the design and logic of a 7-segment display digital circuit. The document includes a schematic, a truth table, Boolean expressions for each segment, Karnaugh maps, and a logic circuit visualization. ### Schematic Diagram A 7-segment display consists of seven LEDs labeled as segments a through g. Each segment can be independently lit to display numerals from 0 to 9. Inputs are labeled A, B, and C, and outputs correspond to each segment. ### Truth Table The truth table maps the combination of inputs (A, B, C) to the segments that need to be active (a, b, c, d, e, f, g) for numerals 0 through 7. \[ \begin{array}{ccccccccccc} A & B & C & a & b & c & d & e & f & g & \text{Number Display} \\ 0 & 0 & 0 & 1 & 1 & 1 & 1 & 1 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 & 1 & 1 & 0 & 0 & 0 & 0 & 1 \\ 0 & 1 & 0 & 1 & 1 & 0 & 1 & 1 & 0 & 1 & 2 \\ 0 & 1 & 1 & 1 & 1 & 1 & 1 & 0 & 0 & 1 & 3 \\ 1 & 0 & 0 & 0 & 1 & 1 & 0 & 0 & 1 & 1 & 4 \\ 1 & 0 & 1 & 1 & 0 & 1 & 1 & 0 & 1 & 1 & 5 \\ 1 & 1 & 0 & 1 & 0 & 1 & 1 & 1 & 1 & 1 & 6 \\ 1 & 1 & 1 & 1 & 1 & 1 & 0 & 0 & 0 & 0 & 7 \\ \end{array} \] ### Boolean Expressions for All Segments Each segment has a unique Boolean expression derived from the Karnaugh maps: - **Segment a:** \(
Expert Solution
Step 1

Demorgan' theorem:

(A+B)'= A'.B'

(A.B)'=A'+B'

 

 

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