√ √ - 6(r cos(0))rdrd0 D = {(r, 0) | 0 ≤ r ≤ 5 + sin(0), 0π ≤ 0 ≤ = π}. Hint: The integral and region is defined in polar coordinates. T 3 п 4 5 k 4 T 2 T 0 1 2 3 4 5 71 0 0

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