68. In the presence of NH 3, Cu+2 forms the complex ion Cu(NH3) 4+2. If the equilibrium concentrations of Cu+2 and Cu(NH3) 4+ are 1.8 x 10-17 M and 1.0 x 10-3 M, respectively, in a 1.5 M NH3 solution, calculate the value for the overall formation constant of Cu(NH3)+2. Cu+2 + 4 NH3 -> Cu(NH3) 4+2

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter16: Solubility And Complex Ion Equilibria
Section: Chapter Questions
Problem 68E: In the presence of NH3, Cu2+ forms the complex ion Cu(NH3)42+. If the equilibrium concentrations of...
Question
68. In the presence of NH 3, Cu+2 forms the complex ion
Cu(NH3) 4+2. If the equilibrium concentrations of Cu+2 and
Cu(NH3) 4+ are 1.8 x 10-17 M and 1.0 x 10-3 M, respectively, in
a 1.5 M NH3 solution, calculate the value for the overall
formation constant of Cu(NH3)+2.
Cu+2 + 4 NH3 -> Cu(NH3) 4+2
Transcribed Image Text:68. In the presence of NH 3, Cu+2 forms the complex ion Cu(NH3) 4+2. If the equilibrium concentrations of Cu+2 and Cu(NH3) 4+ are 1.8 x 10-17 M and 1.0 x 10-3 M, respectively, in a 1.5 M NH3 solution, calculate the value for the overall formation constant of Cu(NH3)+2. Cu+2 + 4 NH3 -> Cu(NH3) 4+2
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