68. In the presence of NH 3, Cu+2 forms the complex ion Cu(NH3) 4+2. If the equilibrium concentrations of Cu+2 and Cu(NH3) 4+ are 1.8 x 10-17 M and 1.0 x 10-3 M, respectively, in a 1.5 M NH3 solution, calculate the value for the overall formation constant of Cu(NH3)+2. Cu+2 + 4 NH3 -> Cu(NH3) 4+2

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section17.6: Equilibria Involving Complex Ions
Problem 1.3ACP: Use the formation constant of [Au(CN)2] in Appendix K to determine the equilibrium concentration of...
Question
68. In the presence of NH 3, Cu+2 forms the complex ion
Cu(NH3) 4+2. If the equilibrium concentrations of Cu+2 and
Cu(NH3) 4+ are 1.8 x 10-17 M and 1.0 x 10-3 M, respectively, in
a 1.5 M NH3 solution, calculate the value for the overall
formation constant of Cu(NH3)+2.
Cu+2 + 4 NH3 -> Cu(NH3) 4+2
Transcribed Image Text:68. In the presence of NH 3, Cu+2 forms the complex ion Cu(NH3) 4+2. If the equilibrium concentrations of Cu+2 and Cu(NH3) 4+ are 1.8 x 10-17 M and 1.0 x 10-3 M, respectively, in a 1.5 M NH3 solution, calculate the value for the overall formation constant of Cu(NH3)+2. Cu+2 + 4 NH3 -> Cu(NH3) 4+2
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