68. Each reaction is allowed to come to equilibrium, and then the volume is changed as indicated. Predict the effect (shift right, shift left, or no effect) of the indicated volume change. a. CO(g) + H2O(g)=CO,(g) + H2(g) (volume is decreased) b. PC13(g) + Cl2(8) = PClg(g) (volume is increased) c. CaCO3(s) = CaO(s) + CO2(g) (volume is increased)

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**68. Volume Change Effects on Chemical Equilibria**

Each reaction is allowed to come to equilibrium, and then the volume is changed as indicated. Predict the effect (shift right, shift left, or no effect) of the indicated volume change.

a. CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g) (volume is decreased)  
- Since the number of moles of gas is the same on both sides of the equation (2 moles reactants vs. 2 moles products), decreasing the volume has no effect on the equilibrium position.

b. PCl₃(g) + Cl₂(g) ⇌ PCl₅(g) (volume is increased)  
- An increase in volume favors the side with more moles of gas. Since there are 2 moles of gas on the reactants side and 1 mole on the products side, the equilibrium will shift to the left.

c. CaCO₃(s) ⇌ CaO(s) + CO₂(g) (volume is increased)  
- Since solids do not count towards the gas volume change, an increase in volume will shift the equilibrium to the right, favoring the production of CO₂(g).
Transcribed Image Text:**68. Volume Change Effects on Chemical Equilibria** Each reaction is allowed to come to equilibrium, and then the volume is changed as indicated. Predict the effect (shift right, shift left, or no effect) of the indicated volume change. a. CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g) (volume is decreased) - Since the number of moles of gas is the same on both sides of the equation (2 moles reactants vs. 2 moles products), decreasing the volume has no effect on the equilibrium position. b. PCl₃(g) + Cl₂(g) ⇌ PCl₅(g) (volume is increased) - An increase in volume favors the side with more moles of gas. Since there are 2 moles of gas on the reactants side and 1 mole on the products side, the equilibrium will shift to the left. c. CaCO₃(s) ⇌ CaO(s) + CO₂(g) (volume is increased) - Since solids do not count towards the gas volume change, an increase in volume will shift the equilibrium to the right, favoring the production of CO₂(g).
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