6.66b SOLVE THE SUBPARTS FOR (b)a)The direction of the IM (impending motion) of the Block is _____degrees.b)The direction of the IM (impending motion) of the Wedge is _____degrees.c)The magnitude of the angle that the R1 force is off the vertical is _____degrees.d)The magnitude of the angle that the R2 force is off the vertical is _____degrees.e)The magnitude of the angle that the R3 force is off the horizontal is _____degrees.f)The magnitude of R1 (reaction force on Surface-1) is _____lb.g)The magnitude of R2 (reaction force on Surface-2) is _____lb.h)The magnitude of R3 (reaction force on Surface-3) is _____lb.i)The magnitude of maximum force P that will not initiate motion of the system is _____lb.NOTE:Submit 5 Sig Fig. **Problem 6/66: Static Friction and Force Analysis**The scenario presented involves a 100-lb body resting on a 15-degree wedge. The coefficient of static friction (μs) between the 100-lb body and the wedge is given as 0.20. The objective is to determine the magnitude of the force \( P \) required to begin raising the 100-lb body under two conditions:1. **Condition (a):** Rollers with negligible friction are present under the wedge.2. **Condition (b):** The rollers are removed, and the coefficient of static friction (\( μs = 0.20 \)) applies to the surface in contact with the wedge.**Diagram Explanation:**- The diagram illustrates the setup: a block labeled ‘100 lb’ is positioned on an inclined wedge which has an angle of 15 degrees.- The wedge itself is resting on rollers in condition (a), shown as small circles beneath it, which implies minimal resistance due to friction.- An arrow labeled \( P \) represents the force applied horizontally to the wedge.- For condition (b), assume these rollers are removed, so static friction is now also acting between the surface under the wedge and the ground.The aim is to solve for the force \( P \) under both conditions using principles of equilibrium and friction.

Disclaimer: Since you have posted a question with multiple sub-parts, we will solve the first three…

Answered: 6/66 The coefficient of static friction…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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6.66b SOLVE THE SUBPARTS FOR (b)

a)The direction of the IM (impending motion) of the Block is _____degrees.

b)The direction of the IM (impending motion) of the Wedge is _____degrees.

c)The magnitude of the angle that the R₁ force is off the vertical is _____degrees.

d)The magnitude of the angle that the R₂ force is off the vertical is _____degrees.

e)The magnitude of the angle that the R₃ force is off the horizontal is _____degrees.

f)The magnitude of R₁ (reaction force on Surface-1) is _____lb.

g)The magnitude of R₂ (reaction force on Surface-2) is _____lb.

h)The magnitude of R₃ (reaction force on Surface-3) is _____lb.

The magnitude of maximum force P that will not initiate motion of the system is _____lb.

NOTE:

Submit 5 Sig Fig.

**Problem 6/66: Static Friction and Force Analysis**

The scenario presented involves a 100-lb body resting on a 15-degree wedge. The coefficient of static friction (μs) between the 100-lb body and the wedge is given as 0.20. The objective is to determine the magnitude of the force \( P \) required to begin raising the 100-lb body under two conditions:

1. **Condition (a):** Rollers with negligible friction are present under the wedge.
2. **Condition (b):** The rollers are removed, and the coefficient of static friction (\( μs = 0.20 \)) applies to the surface in contact with the wedge.

**Diagram Explanation:**

- The diagram illustrates the setup: a block labeled ‘100 lb’ is positioned on an inclined wedge which has an angle of 15 degrees.
- The wedge itself is resting on rollers in condition (a), shown as small circles beneath it, which implies minimal resistance due to friction.
- An arrow labeled \( P \) represents the force applied horizontally to the wedge.
- For condition (b), assume these rollers are removed, so static friction is now also acting between the surface under the wedge and the ground.

The aim is to solve for the force \( P \) under both conditions using principles of equilibrium and friction.

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