66. Using the bond energies in Table 7.3, determine the approximate enthalpy change for each of the following reactions: (a) Cl, (g) + 3F,(g) → 2CIF,(g) (b) H,C= CH,(g) + H,(g) - — Н,ССН, (g) Solution (a) -807 kJ; DH° = ED De-c + 4Dc-H + Dµ-H - Dc-c - 6Dc-H : 611 + 4(415) + 436 – 345 – 6(415) = -128 kJ bonds broken bonds formed (b) %3D

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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 69E: Using the data in Appendix G, calculate the standard enthalpy change for each of the following...
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How did we get 807kJ from question a?how did we get 128kJ for b ?is there a step by step explanation?
66. Using the bond energies in Table 7.3, determine the approximate enthalpy change for each of
the following reactions:
(a) Cl, (g) + 3F,(g)
→ 2CIF, (g)
(b) H,C=CH,(g) + H,(g) → H,CCH,(g)
Solution
(a) -807 kJ;
ED
De-c + 4Dc-H + Du-H - Dc-c - 6Dc-H:
= 611 + 4(415) + 436 -
= -128 kJ
DH°
ZDbonds formed
bonds broken
%3D
C-C
(b)
345 - 6(415)
|
Transcribed Image Text:66. Using the bond energies in Table 7.3, determine the approximate enthalpy change for each of the following reactions: (a) Cl, (g) + 3F,(g) → 2CIF, (g) (b) H,C=CH,(g) + H,(g) → H,CCH,(g) Solution (a) -807 kJ; ED De-c + 4Dc-H + Du-H - Dc-c - 6Dc-H: = 611 + 4(415) + 436 - = -128 kJ DH° ZDbonds formed bonds broken %3D C-C (b) 345 - 6(415) |
Bond
Bond Energy
Bond
Bond Energy
Bond
Bond Energy
H-H
436
C-S
260
F-CI
255
H-C
415
C-CI
330
F-Br
235
H-N
390
C-Br
275
Si-Si
230
H-O
464
C-I
240
SI-P
215
H-F
569
N-N
160
Si-S
225
H-Si
395
N = N
418
Si-CI
359
H-P
320
N = N
946
Si-Br
290
H-S
340
N-O
200
Si-l
215
H-CI
432
N-F
270
P-P
215
H-Br
370
NAP
210
P-S
230
H-I
295
N-CI
200
P-CI
330
C-C
345
N-Br
245
P-Br
270
C = C
611
O-0
140
P-I
215
C = C
O = 0
S-S
215
837
498
C-N
290
O-F
160
S-CI
250
C = N
615
O-Si
370
S-Br
215
C = N
O-P
350
CI-CI
243
891
C-O
350
O-CI
205
CI-Br
220
C = 0
741
200
CI-I
210
MacBook Air
C = 0
1080
F-F
160
Br-Br
190
C-F
439
F-Si
540
Br-l
180
C-Si
360
F-P
489
150
C-P
265
F-S
285
Transcribed Image Text:Bond Bond Energy Bond Bond Energy Bond Bond Energy H-H 436 C-S 260 F-CI 255 H-C 415 C-CI 330 F-Br 235 H-N 390 C-Br 275 Si-Si 230 H-O 464 C-I 240 SI-P 215 H-F 569 N-N 160 Si-S 225 H-Si 395 N = N 418 Si-CI 359 H-P 320 N = N 946 Si-Br 290 H-S 340 N-O 200 Si-l 215 H-CI 432 N-F 270 P-P 215 H-Br 370 NAP 210 P-S 230 H-I 295 N-CI 200 P-CI 330 C-C 345 N-Br 245 P-Br 270 C = C 611 O-0 140 P-I 215 C = C O = 0 S-S 215 837 498 C-N 290 O-F 160 S-CI 250 C = N 615 O-Si 370 S-Br 215 C = N O-P 350 CI-CI 243 891 C-O 350 O-CI 205 CI-Br 220 C = 0 741 200 CI-I 210 MacBook Air C = 0 1080 F-F 160 Br-Br 190 C-F 439 F-Si 540 Br-l 180 C-Si 360 F-P 489 150 C-P 265 F-S 285
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