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64584@q.164 e. What is the approximate molar mass of the metal? (Use Eq. 4.) joules/g C g/mol

64584@q.164 e. What is the approximate molar mass of the metal? (Use Eq. 4.) joules/g C g/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help with #1 part e. What is the molar mass of the metal? Also please explain. I cannot find how to anywhere.
Experiment 14 Advance Study Assignment: Heat Effects and Calorimetry 1. A metal sample weighing 147.90 g and at a temperature of 99.5°C was placed in 49.73 g of water in a calo- rimeter at 23.0°C. At equilibrium the temperature of the water and metal was 41.8°C. What was At for the water? (At = fnal - tinitial) a. 9.5 4t< (418を -23.62 18.8% 18.8 °C 49.739 - 23,6°C b. What was At for the metal? At= (4,8% - 19.5) = 57.72 -57.7 C c. How much heat flowed into the water? (Take the specific heat of the water to be 4.18 J/g°C.) AH=4,1E) = * 1°C e latm 99. x 4.18 ad 3907.98 joules 3907.98) 319.77 3911.72 O 4.1A d. Calculate the specific heat of the metal, using Equation 3. +7フm2b 3967.98 J= (147969) Cs•(57.7C) 4579 J/gc=Cs 04579 joules/g°C o4584@4.184 e. What is the approximate molar mass of the metal? (Use Eq. 4.) g/mol 2. When 4.98 g of NaOH was dissolved in 49.72 g of water in a calorimeter at 23.7°C, the temperature of the solution went up to 50.1°C. M= 4.98g 99.725 ti= 23-77 っ 50° Is this dissolution reaction exothermic?_Yes Why? a. ti=て The rm resultred in heet increese the of b. Calculate qH,0, using Equation 1. e mes Ak 9. 5486.76 joules 9= 5484.70) c. Find AH for the reaction as it occurred in the calorimeter (Eq. 5). AHe-9, - C6036.3 AH = joules 4= C036.25J さ G634.33 A#ニー9 19=Gの%.る (continued on following page) - (G0363)= -G036.3 AH
Transcribed Image Text:Experiment 14 Advance Study Assignment: Heat Effects and Calorimetry 1. A metal sample weighing 147.90 g and at a temperature of 99.5°C was placed in 49.73 g of water in a calo- rimeter at 23.0°C. At equilibrium the temperature of the water and metal was 41.8°C. What was At for the water? (At = fnal - tinitial) a. 9.5 4t< (418を -23.62 18.8% 18.8 °C 49.739 - 23,6°C b. What was At for the metal? At= (4,8% - 19.5) = 57.72 -57.7 C c. How much heat flowed into the water? (Take the specific heat of the water to be 4.18 J/g°C.) AH=4,1E) = * 1°C e latm 99. x 4.18 ad 3907.98 joules 3907.98) 319.77 3911.72 O 4.1A d. Calculate the specific heat of the metal, using Equation 3. +7フm2b 3967.98 J= (147969) Cs•(57.7C) 4579 J/gc=Cs 04579 joules/g°C o4584@4.184 e. What is the approximate molar mass of the metal? (Use Eq. 4.) g/mol 2. When 4.98 g of NaOH was dissolved in 49.72 g of water in a calorimeter at 23.7°C, the temperature of the solution went up to 50.1°C. M= 4.98g 99.725 ti= 23-77 っ 50° Is this dissolution reaction exothermic?_Yes Why? a. ti=て The rm resultred in heet increese the of b. Calculate qH,0, using Equation 1. e mes Ak 9. 5486.76 joules 9= 5484.70) c. Find AH for the reaction as it occurred in the calorimeter (Eq. 5). AHe-9, - C6036.3 AH = joules 4= C036.25J さ G634.33 A#ニー9 19=Gの%.る (continued on following page) - (G0363)= -G036.3 AH
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