63. A sample of unknown metal is placed in a graduated cylinder containing water. The mass of the sample is 37.5 g, and the water levels before and after adding the sample to the cylinder are as shown in the figure. Which metal in the following list is most likely the sample? (d is the density of the metal.) Vi = 7 ml and Vf = 20.5 ml (a) Mg, d = 1.74 g/cm3 (b) Fe, d = 7.87 g/cm3 (c) (c) Ag, d = 10.5 g/cm3 (d) Al, d = 2.70 g/cm3 (e) Cu, d = 8.96 g/cm3 (f) Pb, d = 11.3 g/cm3
Carbohydrates
Carbohydrates are the organic compounds that are obtained in foods and living matters in the shape of sugars, cellulose, and starch. The general formula of carbohydrates is Cn(H2O)2. The ratio of H and O present in carbohydrates is identical to water.
Starch
Starch is a polysaccharide carbohydrate that belongs to the category of polysaccharide carbohydrates.
Mutarotation
The rotation of a particular structure of the chiral compound because of the epimerization is called mutarotation. It is the repercussion of the ring chain tautomerism. In terms of glucose, this can be defined as the modification in the equilibrium of the α- and β- glucose anomers upon its dissolution in the solvent water. This process is usually seen in the chemistry of carbohydrates.
L Sugar
A chemical compound that is represented with a molecular formula C6H12O6 is called L-(-) sugar. At the carbon’s 5th position, the hydroxyl group is placed to the compound’s left and therefore the sugar is represented as L(-)-sugar. It is capable of rotating the polarized light’s plane in the direction anticlockwise. L isomers are one of the 2 isomers formed by the configurational stereochemistry of the carbohydrates.
![**Question 63:**
A sample of unknown metal is placed in a graduated cylinder containing water. The mass of the sample is 37.5 g, and the water levels before and after adding the sample to the cylinder are shown in the figure. Which metal in the following list is most likely the sample? (d is the density of the metal.)
- Initial volume (Vi) = 7 ml
- Final volume (Vf) = 20.5 ml
**Options:**
(a) Mg, \(d = 1.74 \, \text{g/cm}^3\)
(b) Fe, \(d = 7.87 \, \text{g/cm}^3\)
(c) Ag, \(d = 10.5 \, \text{g/cm}^3\)
(d) Al, \(d = 2.70 \, \text{g/cm}^3\)
(e) Cu, \(d = 8.96 \, \text{g/cm}^3\)
(f) Pb, \(d = 11.3 \, \text{g/cm}^3\)
**Explanation:**
The volume of the metal sample is found by the displacement of water, calculated as follows:
\[ \text{Volume of sample} = Vf - Vi = 20.5 \, \text{ml} - 7 \, \text{ml} = 13.5 \, \text{ml} \]
Using the formula for density, \(\text{Density} = \frac{\text{Mass}}{\text{Volume}}\), the density of the sample can be calculated:
\[ \text{Density} = \frac{37.5 \, \text{g}}{13.5 \, \text{ml}} = 2.78 \, \text{g/cm}^3 \]
Matching this calculated density with the options provided, the metal is most likely Aluminum (Al) with \(d = 2.70 \, \text{g/cm}^3\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1d11287-1368-47e9-838e-2b72d8c00c5b%2Ff93a86b8-795e-4d76-8b81-c7c929ef768c%2Ffsva49c_processed.jpeg&w=3840&q=75)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
