78. A capacitor is constructed from two square, metal-lic plates of sides and separation d. Charges +Qand -Q are placed on the plates, and the power sup-ply is then removed. A material of dielectric constantK is inserted a distance x into the capacitor as shownin Figure P26.78. Assumed is much smaller than x.(a) Find the equivalent capacitance of the device.(b) Calculate the energy storedin the capacitor. (c) Findthe direction and magnitude of the force exerted by theplates on the dielectric. (d) Obrain a numerical valuefor the force when x /2, assuming (= 5.00 cm, dD2.00 mm. the dielectric is glass (K = 4.50), and thecapacitor was charged to 2:00 x 10 V before thedielectric was inserted, Suggestion: The system can beconsidered as two capacitors connected in parallel.Figure P26.78 63. A 10.0-uF capacitor is chargedto 15.0 V. It is next connected inseries with an uncharged 5.00-pFcapacitor. The series combina-tion is finally connected acrossa 50.0-V battery as diagrammedin Figure P26.63. Find the newpotential differences acTOSs the5.00-uF and 10.0-pFafter the switch is thrown closed.5.00 pF10.0µFAV = 15.0V50.0 V

Given : The circuit diagram 2 series connected capacitors of 5 micro Farad and 10 micro Farad…

63. A 10.0-µF capacitor is charged to 15.0 V. It is next connected in series with an uncharged 5.00-µF capacitor. The series combina- tion is finally connected across a 50.0-V battery as diagrammed in Figure P26.63. Find the new potential differences across the 5.00-uF and 10.0-uF capacitors after the switch is thrown closed. 5.00 uF 10.0µF AV = 15.0V 50.0 V

63. A 10.0-µF capacitor is charged to 15.0 V. It is next connected in series with an uncharged 5.00-µF capacitor. The series combina- tion is finally connected across a 50.0-V battery as diagrammed in Figure P26.63. Find the new potential differences across the 5.00-uF and 10.0-uF capacitors after the switch is thrown closed. 5.00 uF 10.0µF AV = 15.0V 50.0 V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Two capacitors having capacitances of 10.0 µF and 20.0 µF are connected in series across a 30.0 volt…

A: Given data- two capacitors C1=10.0 μF, and C2=20.0 μF voltage V=30.0 volt

Q: Two Capacitors are connected in parallel. C1=100 μF and C2=200 μF. What total amount of energy will…

A: The effective capacitance of the combination, C=C1+C2C=100 μF+200 μFC=300 μF

Q: A combination of series and parallel connections of capacitors is shown in the figure. The sizes of…

Q: A 13.0-uF capacitor and a 50.0-μF capacitor are charged by being connected across separate 45.0-V…

A: It is given that, . The battery voltage is .

Q: For the system of four capacitors shown in Figure P26.19, find (a) the equivalent capacitance of the…

A: Given Capacitance C1=3μF,C2=6μF, C3=2μF ,C4=4μF Potential difference V=90V

Q: Three capacitors are connected to a battery as shown in Figure P26.22. Their capacitances are C =…

A: "As per the guidelines the i solved the first three subpart". (a) The series combination of the…

Q: A 3.25-μF and a 6.56-μF capacitor are connected in series across a 30.0-V battery. A 9.05-μF…

Q: #16 Charge and energy stored in a series configuration Suppose two 10.0 µF capacitors are in series.…

A: Given : V=5 V C=10x10-6 F for both capacitors We have to find the equivalent capacitance and the…

Q: •• A battery with an emf of 60 V is connected to the two capacitors shown in Figure P26.620.…

Q: A parallel-plate capacitor is made of two square metals, each of area A= 0.50 m², and separated by a…

A: We know that the formula of the electric capacitance is given as C = ε0Ad ----- eq1 Where ε0 is…

Q: With the switch in position A, the C1 = 10.2 r capacitor in the figure below is fully charged by the…

Q: 48. Each capacitor in the combination shown in Figure P26.48 has a breakdown voltage of 15.0 V. What…

Q: A 5-μF capacitor, C1, and a 15-μF capacitor, C2, are connected in series. If the charge stored in C1…

A: Given value--- C1 = 5 micro F. C2 = 15 micro F. charge stored in C1 equals 90 μC. We have to…

Q: Two fully charged capacitors are in series across a 50V source. If the first one is a 1 micro Farad…

Q: A 10.0-µF capacitor is charged to 15.0 V. It is next connected in 5.00раF 10.0 µF series with an…

Q: A 9.4-μF and a 3.1-μF capacitor are connected in series across a 24-V battery. What voltage is…

A: Given value--- C1 = 9.4-μF. C2 = 3.1-μF. Voltage V1 = 24 V. We have to find--- What voltage is…

Q: Three capacitors are connected as shown in the figure. C1 = 5.2 μF, C2 = 14.4 μF, C3 = 4.5 μF. The…

A: a) Expression for energy stored in the capacitor is U=12Ceq∆V2 (b) Capacitors C1 and C2 are in…

Q: Three capacitors of capacitances C1 = 1.8 μF, C2 = 6.55 μF, and C3 = 4.66 μF are connected in…

A: A capacitor is a device used for storing charges. Charge in a capacitor is given by, q = CV When…

Q: Two capacitors with capacitances of 2.0 and 3.6 uF, respectively, are connected in series. The…

A: Capacitance, C1 = 2 μFCapacitance, C2 = 3.6 μFSystem is connected to 40 V battery. Charge on 2 μF is…

Q: A 1.0-µF and a 2.0-µ F capacitor are connected in series across a 3.0-V battery. What is the voltage…

Q: Three capacitors are connected in series. The equivalent capacitance of this combination is 2.82 µF.…

Q: Find the equivalent capacitance between points a and b in the combination of capacitors shown in…

A: Equivalent capacitance, Ce

Q: Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is…

Q: uppose you have a 9.00 V battery, a 3.6 μF capacitor, and a 8.05 μF capacitor. Part (a) Find the…

A: we have given 9.00 V battery, C1= 3.6 μF capacitor, and C2= 8.05 μF capacitor.

Q: Consider two capacitors of 20 µF and 10 µF. The first is charged by a 18 V battery and disconnected;…

Concept explainers

Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.

Question

78. A capacitor is constructed from two square, metal-
lic plates of sides and separation d. Charges +Q
and -Q are placed on the plates, and the power sup-
ply is then removed. A material of dielectric constant
K is inserted a distance x into the capacitor as shown
in Figure P26.78. Assumed is much smaller than x.
(a) Find the equivalent capacitance of the device.
(b) Calculate the energy storedin the capacitor. (c) Find
the direction and magnitude of the force exerted by the
plates on the dielectric. (d) Obrain a numerical value
for the force when x /2, assuming (= 5.00 cm, dD
2.00 mm. the dielectric is glass (K = 4.50), and the
capacitor was charged to 2:00 x 10 V before the
dielectric was inserted, Suggestion: The system can be
considered as two capacitors connected in parallel.
Figure P26.78

63. A 10.0-uF capacitor is charged
to 15.0 V. It is next connected in
series with an uncharged 5.00-pF
capacitor. The series combina-
tion is finally connected across
a 50.0-V battery as diagrammed
in Figure P26.63. Find the new
potential differences acTOSs the
5.00-uF and 10.0-pF
after the switch is thrown closed.
5.00 pF
10.0µF
AV = 15.0V
50.0 V

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

= 12.0 V battery, and the C2 = 9.41 capacitor is uncharged. With the switch in position A, the C1 = 10.2 uF capacitor in the figure below is fully charged by the E A S C2 The switch is now moved to position B. As a result, charge flows between the capacitors until they have the same voltage across their plates. Calculate this voltage.
A power supply is connected in series to a 3 mF capacitor. What voltage does the power supply need to generate so that when the capacitor is fully charged, it has 5 J of energy stored in it? 3333.33 V 262.32 V 57.73 V None of the above 40.82 V
Two capacitors have capacitances of 2.22 μF and 0.514 μF. Determine the equivalent capacitance if they are connected in parallel and in series. (a) in parallel (b) in series μF UF
Four capacitors are connected as shown. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking ΔVab = 15.0 V.
Two (2.80x10^0) µF capacitors are connected in parallel with a (5.0x10^1) V DC power supply. After the capacitors are fully charged, what is the combined electric potential energy stored in the capacitors? Give your answer in joules (J) using scientific notation.
5. A 12.0 V battery and 3 uncharged capacitors сарacitances С1 %3D C2 = 6.00 µF, and C3 µF. The switch is thrown to the left side until capacitor 1 is fully charged. Then the switch is thrown to the right. What is the final charge on (a) capacitor 1, (b) capacitor 2, and (c) of Vo 4.00 µF, C3: = 3.00 %3D capacitor 3?
The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 360 V , which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 10 μs , and the average power dissipated in the flashlamp is 1.0×105 W . What is the capacitance of the capacitor?
Two capacitors are connected in series with a 12.0 V battery. Find the charge on each capacitor. C1=2.5 microfarads (uf) and C2=6.5 microfarads (uf).
Two capacitors with capacitances of 1.0 and 0.5 µF, respectively, are connected inparallel. The system is connected to a 100 V battery. What charge accumulates on the 1.0µF capacitor?
Four capacitors are connected as shown in Figure P26.17. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking ΔVab= 15V
Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in µC)? q′1= 421 µC q′2= 234 µC (b) What If? What is the resulting charge on each capacitor (in µC) if they are instead charged as a series combination and then connected positive plate to positive plate and negative plate to negative plate? q′1= q′2= solved the first two I need help with the bottom two it has to be in the format of the first two thank you
When connected in series, two capacitors have an equivalent capacitance of 1.60 µF. The same two capacitors have an equivalent capacitance of 14.0 µF when connected in parallel. What is the capacitance of each of the capacitors?