60. The geometric, logarithmic, and arithmetic mean inequality a. Show that the graph of e* is concave up over every interval of x-values. b. Show, by reference to the accompanying figure, that if 0 < a < b then Inb elna + elnb (Ina+Inb)/2. (Inb – Ina) < • (In b – In a). e* dx < 2 Ina y = e* B х In a + In b In b In a 2 NOT TO SCALE c. Use the inequality in part (b) to conclude that b – a a + b Vab Inb – Ina 2 This inequality says that the geometric mean of two positive numbers is less than their logarithmic mean, which in turn is less than their arithmetic mean.
60. The geometric, logarithmic, and arithmetic mean inequality a. Show that the graph of e* is concave up over every interval of x-values. b. Show, by reference to the accompanying figure, that if 0 < a < b then Inb elna + elnb (Ina+Inb)/2. (Inb – Ina) < • (In b – In a). e* dx < 2 Ina y = e* B х In a + In b In b In a 2 NOT TO SCALE c. Use the inequality in part (b) to conclude that b – a a + b Vab Inb – Ina 2 This inequality says that the geometric mean of two positive numbers is less than their logarithmic mean, which in turn is less than their arithmetic mean.
Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
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Chapter1: Functions And Models
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Question
![60. The geometric, logarithmic, and arithmetic mean inequality
a. Show that the graph of e* is concave up over every interval of
x-values.
b. Show, by reference to the accompanying figure, that if
0 < a < b then
Inb
elna + elnb
(Ina+Inb)/2. (Inb – Ina) <
• (In b – In a).
e* dx <
2
Ina
y = e*
B
х
In a + In b
In b
In a
2
NOT TO SCALE
c. Use the inequality in part (b) to conclude that
b – a
a + b
Vab
Inb – Ina
2
This inequality says that the geometric mean of two positive
numbers is less than their logarithmic mean, which in turn is
less than their arithmetic mean.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F690b93c1-a36f-4ba6-8aab-a0d4b7e86b05%2F69c4db07-a098-4b10-b150-1ff9c6c5b6e8%2Fqvr40ag.png&w=3840&q=75)
Transcribed Image Text:60. The geometric, logarithmic, and arithmetic mean inequality
a. Show that the graph of e* is concave up over every interval of
x-values.
b. Show, by reference to the accompanying figure, that if
0 < a < b then
Inb
elna + elnb
(Ina+Inb)/2. (Inb – Ina) <
• (In b – In a).
e* dx <
2
Ina
y = e*
B
х
In a + In b
In b
In a
2
NOT TO SCALE
c. Use the inequality in part (b) to conclude that
b – a
a + b
Vab
Inb – Ina
2
This inequality says that the geometric mean of two positive
numbers is less than their logarithmic mean, which in turn is
less than their arithmetic mean.
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