60. The geometric, logarithmic, and arithmetic mean inequality a. Show that the graph of e* is concave up over every interval of x-values. b. Show, by reference to the accompanying figure, that if 0 < a < b then Inb elna + elnb (Ina+Inb)/2. (Inb – Ina) < • (In b – In a). e* dx < 2 Ina y = e* B х In a + In b In b In a 2 NOT TO SCALE c. Use the inequality in part (b) to conclude that b – a a + b Vab Inb – Ina 2 This inequality says that the geometric mean of two positive numbers is less than their logarithmic mean, which in turn is less than their arithmetic mean.

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60. The geometric, logarithmic, and arithmetic mean inequality
a. Show that the graph of e* is concave up over every interval of
x-values.
b. Show, by reference to the accompanying figure, that if
0 < a < b then
Inb
elna + elnb
(Ina+Inb)/2. (Inb – Ina) <
• (In b – In a).
e* dx <
2
Ina
y = e*
B
х
In a + In b
In b
In a
2
NOT TO SCALE
c. Use the inequality in part (b) to conclude that
b – a
a + b
Vab
Inb – Ina
2
This inequality says that the geometric mean of two positive
numbers is less than their logarithmic mean, which in turn is
less than their arithmetic mean.
Transcribed Image Text:60. The geometric, logarithmic, and arithmetic mean inequality a. Show that the graph of e* is concave up over every interval of x-values. b. Show, by reference to the accompanying figure, that if 0 < a < b then Inb elna + elnb (Ina+Inb)/2. (Inb – Ina) < • (In b – In a). e* dx < 2 Ina y = e* B х In a + In b In b In a 2 NOT TO SCALE c. Use the inequality in part (b) to conclude that b – a a + b Vab Inb – Ina 2 This inequality says that the geometric mean of two positive numbers is less than their logarithmic mean, which in turn is less than their arithmetic mean.
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