60° В ctric flux through the rectangular surface show gnitude of the electric field in N/C?
Q: A very large flat conducting sheet carries a uniform charge density of 3.82 pC/mm² on its surface.…
A: There is a large conducting sheet.Charge density= 3.82 pC/(mm)2E(r= 7.12 mm)
Q: A nonuniform electric field is given by the expression D = 2у a + z a — Зха y C/m?. Determine the…
A: We have Electric field given by D=2yi^+zj^-3xk^. We need to find Electric flux through a rectangular…
Q: Find the magnitude of the electric flux through the shaded face due to q. Φ = ______
A:
Q: The thin insulating rod is lays on y-axis as shown in picture. The length of the rod is 100 cm.…
A: The position vector of point P is, The position vector of a charged element on the rod is, Also, the…
Q: A thin, flat washer is a disk with an outer diameter of 8.85 cm and a hole in the center with a…
A:
Q: line charge density is 30.0 µC/m, what is the net electric field flux through the wall of the…
A: Given length of the cylinder (L)= 0.350m Radius (r)= 0.070m the linear charge density (i.e, charge…
Q: An electric field of magnitude 5130 N/C is applied along the r axis. Calculate the electric flux…
A:
Q: The electric flux through a square-shaped area of side 5 cm near a large charged sheet is found to be…
A: Given: Side a=5 cm=0.05 m Electric flux ϕ= 3*10^-5 Nm2/C To find the charge density on the sheet.
Given:
Electric flux,
Length A=8 cm
B=40 cm
angle=90-60=30 degree
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- 14 A square insulating sheet The sheet has area. 90.0cm on a side is held horizontally. over its 6.80nC of charge spread uniformly Colculate the electric field at a above the center of the sheet. point 0.0500mm Estimate the electric field at a point 150m above the center of the sheet.Calculate the electric field intensity at a point 18.0cm from the centre of a small conducting sphere that has a charge of -2.8 μC.What is the electric flux through surface C of the figure provided? +2q/ϵ0 −q/ϵ0 0 +q/ϵ0
- An electric point charge of Q = 21.3 nC is placed at the center of a sphere with a radius of r = 46.1 cm. The sphere in this question is only a mathėmatical surface, it is not made out of any physical material. What 'is the electric flux through the surface of this sphere? Submit Answer Tries 0/99 This same point charge is now moved out from the center of the sphere by a distance of 18.9 cm. What is the electric flux through the surface of the sphere now? Submit Answer Tries 0/99YA d- X A line charge of charge density, pl = 0.0001 C/m is of length, 1=2.5 m. Find the electric field component Ey at the point, d=5 m. away from one end as shown in the figure above.For the configuration shown in the figure below, suppose a-5.00 cm, 620.0 cm, and c25.0 om, furthermore, suppose the electric field at a point 16.5 cm from the center is measured to be 3.05 x 10³ N/C radialty inward and the electric field at a point 50.0 cm from the center is of magnitude 161 N/C and points radially outward. From this information, find the following. (Include the sign of the charge in your answer.) (a) the charge on the insulating sphere Do the charges on the conducting shell affect the electric held at this point? C (b) the net charge on the hollow conducting sphere What is the total charge inside a sphere of radius 50 cm? C (6) the charge on the inner surface of the hollow conducting sphere (d) the charge on the outer surface of the hollow conducting sphere Need Help? Ref W
- Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.26 104 N/C as shown in the figure below. (a) Calculate the electric flux through the vertical rectangular surface of the box.A right conical frustrum is placed in a uniform electric field that is parallel to the y axis, as shown. The magnitude of the electric field is 43 N/C. The electric flux measured through the top surface is 2240 N-m?/C, and the electric flux measured through the bottom surface is 4480 N-m²/C. What is the electric flux through the side of the frustrum?