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60 V (+1 t=0 10 ΚΩ Dwww □ V(0) = 10V capacitor voltage right before switch opens is 60V Resistance seen by the capacitor after switch opens is 2k ohms ☐the circuit time constant is 0.16 2 ΚΩ Resistance seen by the capacitor after switch opens is 10k ohms the circuit time constant is 0.08 v(t) = 10*e-12.5t V + v(t) = 40 μF

60 V (+1 t=0 10 ΚΩ Dwww □ V(0) = 10V capacitor voltage right before switch opens is 60V Resistance seen by the capacitor after switch opens is 2k ohms ☐the circuit time constant is 0.16 2 ΚΩ Resistance seen by the capacitor after switch opens is 10k ohms the circuit time constant is 0.08 v(t) = 10*e-12.5t V + v(t) = 40 μF

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The switch has been closed for a long time, and it opens at t=0. Click all that apply

60 V v(0) = 10V t = 0 10 ΚΩ 2 ΚΩ capacitor voltage right before switch opens is 60V Resistance seen by the capacitor after switch opens is 2k ohms the circuit time constant is 0.16 www Resistance seen by the capacitor after switch opens is 10k ohms the circuit time constant is 0.08 v(t) = 10*e-12.5t v After a long time capacitor voltage will approximate zero (discharge) + = 40 μF
Transcribed Image Text:60 V v(0) = 10V t = 0 10 ΚΩ 2 ΚΩ capacitor voltage right before switch opens is 60V Resistance seen by the capacitor after switch opens is 2k ohms the circuit time constant is 0.16 www Resistance seen by the capacitor after switch opens is 10k ohms the circuit time constant is 0.08 v(t) = 10*e-12.5t v After a long time capacitor voltage will approximate zero (discharge) + = 40 μF
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