A half-wave rectifier circuit with C= 100 μF and R= 2.2k 2 has v₁ = 18 cos(2n-60t) volts. The ripple voltage V, is found to be about 1.4 volts peak to peak. Which of the following would NOT be a way to decrease the ripple voltage amplitude? 9152 Dic C www vo

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A half-wave rectifier circuit with C= 100 µF and R= 2.2k 2 has v₁ = 18 cos(2л-60t)
volts. The ripple voltage V₁ is found to be about 1.4 volts peak to peak. Which of
the following would NOT be a way to decrease the ripple voltage amplitude?
Uण
150
ic
www
Vo
Make R= 1 kQ
Change vi to be 18 cos(2л-200t) volts.
Increase the value of C
Make R= 10k Q
Make C= 440 μF
Transcribed Image Text:A half-wave rectifier circuit with C= 100 µF and R= 2.2k 2 has v₁ = 18 cos(2л-60t) volts. The ripple voltage V₁ is found to be about 1.4 volts peak to peak. Which of the following would NOT be a way to decrease the ripple voltage amplitude? Uण 150 ic www Vo Make R= 1 kQ Change vi to be 18 cos(2л-200t) volts. Increase the value of C Make R= 10k Q Make C= 440 μF
Expert Solution
Step 1: Question analysis:

For the given half wave rectifier circuit:

straight C equals 100 straight mu straight F
straight R equals 2.2 straight k straight capital omega
straight V subscript straight i equals 18 cos left parenthesis 2 straight pi.60 straight t right parenthesis space straight V space space so comma space straight f equals 60 Hz
Ripple space voltage space straight V subscript straight r equals 1.4 space straight V space left parenthesis peak space to space peak right parenthesis

For the given options which of the following would not be the way to decrease the ripple voltage amplitude.


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