A half-wave rectifier circuit with C= 100 µF and R= 2.2k 2 has v₁ = 18 cos(2л-60t)volts. The ripple voltage V₁ is found to be about 1.4 volts peak to peak. Which ofthe following would NOT be a way to decrease the ripple voltage amplitude?Uण150icwwwVoMake R= 1 kQChange vi to be 18 cos(2л-200t) volts.Increase the value of CMake R= 10k QMake C= 440 μF

For the given half wave rectifier circuit:For the given options which of the following would not be…

Answered: A half-wave rectifier circuit with C=…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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A half-wave rectifier circuit with C= 100 µF and R= 2.2k 2 has v₁ = 18 cos(2л-60t)
volts. The ripple voltage V₁ is found to be about 1.4 volts peak to peak. Which of
the following would NOT be a way to decrease the ripple voltage amplitude?
Uण
150
ic
www
Vo
Make R= 1 kQ
Change vi to be 18 cos(2л-200t) volts.
Increase the value of C
Make R= 10k Q
Make C= 440 μF

Expert Solution

Step 1: Question analysis:

For the given half wave rectifier circuit:

$straight C equals 100 straight mu straight F straight R equals 2.2 straight k straight capital omega straight V subscript straight i equals 18 cos left parenthesis 2 straight pi.60 straight t right parenthesis space straight V space space so comma space straight f equals 60 Hz Ripple space voltage space straight V subscript straight r equals 1.4 space straight V space left parenthesis peak space to space peak right parenthesis$

For the given options which of the following would not be the way to decrease the ripple voltage amplitude.

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