60 litres of gasoline spreads over a surface area of 10 m² after spillage and evaporates into the stagnant air. The diffusivity of gasoline in the air is 0.65m²/h. The air temperature is 298K. It is assumed the evaporation through a film of 2m thickness of air. The density of gasoline is 720 kg/m³ and molecular weight is 200. The accident happened at 1 atm pressure. The vapor pressure of gasoline at 298K is 76 mmHg. Estimate the time required for total evaporation.
60 litres of gasoline spreads over a surface area of 10 m² after spillage and evaporates into the stagnant air. The diffusivity of gasoline in the air is 0.65m²/h. The air temperature is 298K. It is assumed the evaporation through a film of 2m thickness of air. The density of gasoline is 720 kg/m³ and molecular weight is 200. The accident happened at 1 atm pressure. The vapor pressure of gasoline at 298K is 76 mmHg. Estimate the time required for total evaporation.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:60 litres of gasoline spreads over a surface area of 10 m² after spillage and
evaporates into the stagnant air. The diffusivity of gasoline in the air is 0.65m²/h.
The air temperature is 298K. It is assumed the evaporation through a film of 2m
thickness of air. The density of gasoline is 720 kg/m³ and molecular weight is
200. The accident happened at 1 atm pressure. The vapor pressure of gasoline
at 298K is 76 mmHg. Estimate the time required for total evaporation.
Expert Solution
Step 1
Given
- Volume V=60 litres
- Area A=10 m2
- Diffusivity D=0.65 m2/h
- Air temperature T=298 K
- Film thickness=2 m
- Density of gasoline=720 kg/m3
- Molecular weight of gasoline=200
- Pressure P=1 atm
- Vapor pressure of gasoline(at T)=76 mmHg
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Time required for total evaporation(t)
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