6.70 A/↑Solar Panel0.385 ΩMMBatteryM0.385 Ω0.77 Ωww0.028 0212.40 VMDLED LightM0.77 Ωww7.2 Q0.77 Ω-5.50 VLED Lightwww0.77 Ω0.77 Ωww7.2 Q5.50 VLED Lightat gate0.77 Ω7.2 Q75.50 VRe-draw the full circuit diagram of the system described above. These are the actual values thatshould be used in your calculations. Where possible, simplify and redraw the diagram by combiningseries and parallel resistances.

Given Data:A solar application circuit with,Solar panel,BatteryLED lights and Resistors.To…

Answered: 6.70 A D Solar Panel 0.385 Ω ww Battery…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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6.70 A/
↑
Solar Panel
0.385 Ω
M
M
Battery
M
0.385 Ω
0.77 Ω
ww
0.028 02
12.40 V
MD
LED Light
M
0.77 Ω
ww
7.2 Q
0.77 Ω
-5.50 V
LED Light
www
0.77 Ω
0.77 Ω
ww
7.2 Q
5.50 V
LED Light
at gate
0.77 Ω
7.2 Q
75.50 V
Re-draw the full circuit diagram of the system described above. These are the actual values that
should be used in your calculations. Where possible, simplify and redraw the diagram by combining
series and parallel resistances.

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Follow-up Question

with this simplified circuit, i'm not 100% sure that it's right, because where did my current source go? how can it combine with my voltage source? please help.

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Follow-up Question

when finding thevenin's equivalent voltage, why is 6.70 A multiplied by 0.028 Ohms, the resistance of the voltage source of 12.40V? could you explain why and how that is the thevenin formula that it relates to?

also, I don't understand why the simplified resistance equivalence of 1.568 Ohms was put there. wouldn't it be on the next resistor over in the circuit?

what do the nodes of A & B mean in that final simplified circuit?

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