-6.62 -4.29- -5.02- -5.37 4 KN 5 KN 3.73 3.24 1.04 6.2 KN B 1.96 0.43 4 KN 2.4 KN -2.59- 5.77- 5.09 4.69- 3.14 Specify the member forces of BC, FC, BF.

Q: Create a moment diagram given the FBD and shear diagram (pictured)

A: Draw the bending moment diagram of the given FBD and Shear force diagram.

Q: SITUATION 5. For Items 12-14. 12. Find the force acting on member FE. a. 1.803 kN "T" 1.Şm H b.…

A:

Q: Solve FG only

A: Support reaction: Due to symmetry:AY=12×(2×(0.6+1.24+1.04+1)+1.2)=4.48 KN

Q: all steel are Fy = 345 MPa unless noted otherwise W12x19: d = 30.8864 cm bf = 100mm tf = 8.725 mm tw…

A: Hi! Thank you for the question As per the honor code, We’ll answer the Third question since the…

Q: In the system whose loading condition is given in the figure, in which of the following options is…

A: A = 200cm2Ix = 2000cm4E = 200000 MPaTo determine the force in member DETake force in DE be P.The…

Q: Determine the slope and deflection at point Bof the beam shown by the direct integration method. 50…

A: Solution: Given data: Youngs modulus E=70 GPaMoment of Inertia I=164×106 mm4 Consider flexural…

Q: m bending moment of this beam b.) Replace the existing beam by a wide flange.

A:

Q: What is the internal bending moment at point B (including the sign based on the sign convention for…

A:

Q: 29. Shear force equation for segment AB. * O a. 0.49KN-0.15x2 (KN/m2) O b. 0.49KN-0.16x2 (KN/m2) O…

A: given beam

Q: Circle all zero force members.

A:

Q: Find roller support reaction

A: Given data : The data of point load are: Point load=P Point load=Q Point load=R   Required : Finding…

Q: -5.37 5 KN 6.62- -4.29- -5.02- 4 KN 3.73 3.24 E 1.04 6.2 KN B. 1.96 0.43 C 4 KN 2.4 KN -2.59 5.77-…

A:

Q: 2. Draw the FBD of the entire structure C 18 kN 2 m В 2 m E 2 m A -3.6 m-

A:

Q: B 30 KN 1.5m 1.5m RDx 2m F 2m E 2m RD 50 KN RDy RA

A:

Q: O Ax-4 kN, Ay=D4 kN, By-4.5 kN O Ax-4 kN, Ay%=D1.5 kN, By-1 kN O Ax-4 kN, Ay=1 kN, By=1.5 kN O Ax-4…

A:

Q: Derive the shear force equation,bending moment equation for the beam own. Neglect the weight of the…

A: Uniformly varying load with 2.1kN/m at 7 m span. To calculate shear force and bending moment…

Q: Is frame is statically determinant

A: Given Data  Determine structure is statically determinate or indeterminate.

Q: Problem-4. For the beam shown, determine which type of loading creates maximum positive and maximum…

A: Given beam: Given loading: To determine:  Maximum positive and negative SF, and maximum BM at C

Q: SIT: A built up beam is made up of 1250mm * 9mm web section and two flange sections of 620 x 20mm…

A:

Q: Homework 1-2.2: Find the Reactions 36k 5k/ft 6/ft 3k/ft 2k/ft B-Q 15' 3' 1' 3-1-1 3-1-2 24k/ft 25k|…

A:

Q: B1

A:

Q: Find roller support reaction

A: Given:- A truss is loaded with various point loads The magnitude of the point load at points B, D,…

Q: (1) H.W.:Draw AFD ,SFD an BMD for frames below a) A 40 kN/m 6 m B 4 m 5 m b) 37 kN/m B Hinge 75 kNm…

A:

Q: 12 kN 8 kN C 1 m 3 m 1 m

A: Apply equilibrium condition : ∑MC=0RA×4-12×3+8×1=0RA=7 KN

Q: 1. FROM THE GIVEN TRUSS, DET. THE FF: a. HORIZONTAL REACTION @ J b. VERTICOL REACTION @ J C.…

A:

Q: A light crane runway beam spaced at 125 mm on center longitudinally, throughout its length. The beam…

A: Bending Stress: It is the stress generate during the bending of the beam. Its variation is zero to…

Q: 3. Draw AFD, SFD, BMD of the below structure (Figure:02). 50KN 3 m 80KN 3 m 5m 3 m Figure: 02

A: Assuming that the heap on a segment is applied through the focal point of gravity of its cross area,…

Q: determine the reactions and moments using slope deflection method

A: Using slope deflection method,  Calculation reaction and BMD##AND SFD

Q: 30. Bending moment equation for segment AB. O a. 0.58x(KN)-0.16x3(KN/m2) O b.…

A: Draw the free body diagram. Equilibrium of horizontal forces, ∑Fx=0Ax=0

Q: 14.4 Identify the type of masonry block shown below

A: To identify the given brick masonry.  Brick masonry is used for the construction of wall for…

Q: 89 (KN) 39 (KN/m) 70 (KNm) E 4iS. m) normal Force ? cuting force? moment(NTM) diyagrams!

A:

Q: A 8 m 3 m B 3m- 6 m 1.5 m 1 m

A:

Q: Draw N, V, M diagrams. 9.5 Kn Hinge Q2 = 2.2 KN/m %3D Q2 = 1.6 KN/m II A F M = 6 kNm -7.50 2.56…

A: Finding out SFD and BMD.

Q: M kN.m A B m+1 m+ C W kN/m 3 m 2 m E

A:

Q: A continuous beam is loaded as shown be

A:

Q: Determine force in member FG

A: Support reaction: Apply equilibrium condition:∑ME=0RA×12-32×3-70×6-32×9=0RA=67 KN

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.