Explain -6,000 mmDL 1.5 kN/mLL = 5 kN/mW12X19all steel are Fy= 345 MPaunless notedotherwiseW12x19:d = 30.8864 cmbf = 100mmtf = 8.725 mmtw = 5.925 mmZx = 404.76x10^3 mm3ry = 20.87 mmrx = 122.70 mmJc = 75.34x10^3 mm4Sx = 350x10^3 mm3Cw=3.52x10^10 mm6ly = 1.535x10^6 mm4Ix = 54.11x10^6 mm4What is the section capacity of the beam?A 139.64 kN-mB193.64 kN-mC169.64 kN-mD146.64 kN-mW12X26DW12X26W12x26:A = 4935 mm2ry= 38.20 mmrx = 131.17 mmHINT: Circle denotes simply supported supports or connections.-3,700 mm- What should be the length of the beam so that itsunder plastic lateral torsional buckling? LpA) 884.38 mmB 844.38 mmC) 888.38 mmD 848.38 mmWhat is the moment capacity of the beam and is itadequate?(A) 8.2 kN-m, InadequateB 8.2 kN-m, adequatec) 32.945 kN-m, Inadequate(D) 32.945 kN-m, adequate

Hi! Thank you for the question As per the honor code, We’ll answer the Third question since the…

all steel are Fy = 345 MPa unless noted otherwise W12x19: d = 30.8864 cm bf = 100mm tf = 8.725 mm tw = 5.925 mm Zx = 404.76x10^3 mm3 ry = 20.87 mm rx = 122.70 mm Jc = 75.34x10^3 mm4 Sx= 350x10^3 mm3 Cw=3.52x10^10 mm6 ly = 1.535x10^6 mm4 Ix = 54.11x10^6 mm4 W12X26 -6,000 mm DL = 1.5 kN/m LL = 5 kN/m W12X19 Ө W12X26 W12x26: A = 4935 mm2 ry = 38.20 mm rx = 131.17 mm HINT: Circle denotes simply supported supports or connections. 3,700 mm-