**6.4 Draw the curved arrows that result in the resonance structures below.****Structure (c):**This resonance structure consists of a carbonyl compound with a nitrogen atom. On the left, the oxygen atom is double-bonded to a carbon, and the nitrogen atom carries a negative charge. The resonance structure on the right shows the lone pairs on the nitrogen forming a double bond with the carbon, while the double bond between the oxygen and carbon becomes a single bond, resulting in the oxygen carrying a negative charge. The structures are enclosed in brackets, indicating resonance, and a double-headed arrow between them shows they are resonance forms of the same compound.**Structure (d):**This resonance structure involves a five-membered ring resembling a cyclopentadienyl cation. It shows two resonance forms. The left structure has a positive charge on one of the carbon atoms within the ring. The right structure shifts the positive charge to an adjacent carbon atom in the ring, suggesting electron delocalization. The structures are enclosed in brackets, and a double-headed arrow indicates resonance between these forms.These representations depict electron movement within the molecules, providing insight into resonance stabilization.

Resonance effect - Delocalization of pi or non bonding electrons.

Answered: 6.4 Draw the curved arrows that result…

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6.4 Draw the curved arrows that result in the resonance structures below. [44] [0-0] (c) (d)

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Stereochemistry and Isomerism

Stereochemistry deals with the three-dimensional structure and properties of molecules. It explains the arrangement of atoms and their manipulation within a molecule in a 3D structure. Stereochemistry can be dealt with all types of molecules. Based on the stereochemistry of a molecule, the physical and chemical properties of the molecules vary.

Question

**6.4 Draw the curved arrows that result in the resonance structures below.**

**Structure (c):**
This resonance structure consists of a carbonyl compound with a nitrogen atom. On the left, the oxygen atom is double-bonded to a carbon, and the nitrogen atom carries a negative charge. The resonance structure on the right shows the lone pairs on the nitrogen forming a double bond with the carbon, while the double bond between the oxygen and carbon becomes a single bond, resulting in the oxygen carrying a negative charge. The structures are enclosed in brackets, indicating resonance, and a double-headed arrow between them shows they are resonance forms of the same compound.

**Structure (d):**
This resonance structure involves a five-membered ring resembling a cyclopentadienyl cation. It shows two resonance forms. The left structure has a positive charge on one of the carbon atoms within the ring. The right structure shifts the positive charge to an adjacent carbon atom in the ring, suggesting electron delocalization. The structures are enclosed in brackets, and a double-headed arrow indicates resonance between these forms.

These representations depict electron movement within the molecules, providing insight into resonance stabilization.

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Tutored Practice Problem 6.3.3 COUNTS TOWARDS GRADE Use formal charge and electronegativity to identify best resonance structure. Close Proble Three inequivalent resonance structures for carbonyl sulfide, SCO, are shown below, Assign formal charges to all atoms in the resonance structures and identify the more likely resonance structure. Note: If a row is not needed, leave it blank. 5-c = ö :S=C - ö: :S-C = 0: A B The more likely resonance structure for SCO is [ v Check & Submit Answer Show Approach