6.3.2 In a study of the effects of early Alzheimer's discase on nondeclarative memory, Reber et al. (A-2) used the Category Fluency Test to establish baseline persistence and semantic memory and language abilities. The cight subjects in the sample had Category Fluency Test scores of 11, 10, 6, 3, 11, 10, 9, 11. Assume that the cight subjects constitute a sim- ple random sample from a normally distributcd population of similar subjects with early Alzheimer's discase. (a) What is the point estimate of the population mean? (b) What is the standard deviation of the sample? (c) What is the estimatcd standard error of the sample mean? (d) Construct a 95 percent confidence interval for the population mean category fluency test score. (e) What is the precision of the cstimate? (f) State the probabilistic interpretation of the confidence interval you constructed. (g) State the practical interpretation of the confidecnce interval you constructed.

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Did I calculate (a) through (e) correctly? I am having trouble with f and g.  For g: I am 95% confident that in eight subjects who have a category fluency test score will score somewhere between 6 and 11??

For G: In repeated sampling, this method produces intervals that capture the sample mean in about 95% of samples??

Thank you  

### Understanding Early Alzheimer’s Disease: A Statistical Analysis

#### Study Overview
In a study examining the effect of early Alzheimer’s disease on nondeclarative memory, researchers used the Category Fluency Test to establish baseline persistence and semantic memory and language abilities. The eight subjects in the sample had Category Fluency Test scores of 11, 10, 6, 3, 11, 10, 9, 11.

#### Analysis Breakdown
The following steps detail the statistical analysis performed on the sample data:

1. **Point Estimate of the Population Mean (a)**:
    - Raw scores: \(11, 10, 6, 3, 11, 10, 9, 11\)
    - \[
    \bar{X} = \frac{\sum{X}}{n} = \frac{71}{8} = 8.875
    \]
    - The point estimate of the population mean is 8.875.

2. **Standard Deviation of the Sample (b)**:
    - Calculation:
        \[
        s^2 = \frac{\sum{(X - \bar{X})^2}}{n-1} = \frac{689 - \left(\frac{71^2}{8}\right)}{8-1} = 8.410714286
        \]
        \[
        s = \sqrt{8.410714286} = 2.90012315
        \]
    - The standard deviation \( s \) is 2.90012315.

3. **Estimated Standard Error of the Sample Mean (c)**:
    - Calculation:
        \[
        \sigma_{\bar{X}} = \frac{s}{\sqrt{n}} = \frac{2.90012315}{\sqrt{8}} = 0.3625153938
        \]
    - The estimated standard error is 0.3625153938.

4. **95% Confidence Interval for the Population Mean (d)**:
    - For \( n = 8 \) and \( df = 7 \), the critical value \( t_{c} \) from t-distribution table at 95% confidence is 2.365.
    - Calculation:
        \[
        \bar{X} \pm t_{c} \left( \frac{s}{\sqrt{n}} \right) =
Transcribed Image Text:### Understanding Early Alzheimer’s Disease: A Statistical Analysis #### Study Overview In a study examining the effect of early Alzheimer’s disease on nondeclarative memory, researchers used the Category Fluency Test to establish baseline persistence and semantic memory and language abilities. The eight subjects in the sample had Category Fluency Test scores of 11, 10, 6, 3, 11, 10, 9, 11. #### Analysis Breakdown The following steps detail the statistical analysis performed on the sample data: 1. **Point Estimate of the Population Mean (a)**: - Raw scores: \(11, 10, 6, 3, 11, 10, 9, 11\) - \[ \bar{X} = \frac{\sum{X}}{n} = \frac{71}{8} = 8.875 \] - The point estimate of the population mean is 8.875. 2. **Standard Deviation of the Sample (b)**: - Calculation: \[ s^2 = \frac{\sum{(X - \bar{X})^2}}{n-1} = \frac{689 - \left(\frac{71^2}{8}\right)}{8-1} = 8.410714286 \] \[ s = \sqrt{8.410714286} = 2.90012315 \] - The standard deviation \( s \) is 2.90012315. 3. **Estimated Standard Error of the Sample Mean (c)**: - Calculation: \[ \sigma_{\bar{X}} = \frac{s}{\sqrt{n}} = \frac{2.90012315}{\sqrt{8}} = 0.3625153938 \] - The estimated standard error is 0.3625153938. 4. **95% Confidence Interval for the Population Mean (d)**: - For \( n = 8 \) and \( df = 7 \), the critical value \( t_{c} \) from t-distribution table at 95% confidence is 2.365. - Calculation: \[ \bar{X} \pm t_{c} \left( \frac{s}{\sqrt{n}} \right) =
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