6.16 More confidence interval mistakes and misunderstandings. Suppose that 100 randomly selected members of the Karaoke Channel were asked how much time they typically spend on the site during the week. The sample mean was found to be 3.8 hours. Assume that the population standard deviation is known to be o = 2.9. (a) Cary Oakey computes the 95% confidence interval for the average time on the site as 3.8 ± 1.96(2.9/100). What is his mistake? (b) He corrects this mistake and then states that "95% of the members spend between 3.23 and 4.37 hours a week on the site." What is wrong with his interpretation of this interval? (c) The margin of error is slightly larger than half an hour. To reduce this to roughly 15 minutes, Cary says that the sample size needs to be doubled to 200. What is wrong with this statement?

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6.16 More confidence interval mistakes and
misunderstandings. Suppose that 100 randomly selected
members of the Karaoke Channel were asked how much
time they typically spend on the site during the week. The
sample mean it was found to be 3.8 hours. Assume that
the population standard deviation is known to be o = 2.9.
(a) Cary Oakey computes the 95% confidence interval for
the average time on the site as 3.8 ± 1.96(2.9/100). What
is his mistake?
(b) He corrects this mistake and then states that "95% of
the members spend between 3.23 and 4.37 hours a week
on the site." What is wrong with his interpretation of this
interval?
(c) The margin of error is slightly larger than half an
hour. To reduce this to roughly 15 minutes, Cary says
that the sample size needs to be doubled to 200. What is
wrong with this statement?
Transcribed Image Text:6.16 More confidence interval mistakes and misunderstandings. Suppose that 100 randomly selected members of the Karaoke Channel were asked how much time they typically spend on the site during the week. The sample mean it was found to be 3.8 hours. Assume that the population standard deviation is known to be o = 2.9. (a) Cary Oakey computes the 95% confidence interval for the average time on the site as 3.8 ± 1.96(2.9/100). What is his mistake? (b) He corrects this mistake and then states that "95% of the members spend between 3.23 and 4.37 hours a week on the site." What is wrong with his interpretation of this interval? (c) The margin of error is slightly larger than half an hour. To reduce this to roughly 15 minutes, Cary says that the sample size needs to be doubled to 200. What is wrong with this statement?
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does question say to bring the sample donw by 1/2 or the mean down by 1/2

 

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