6.115 Hydrogen sulfide, H,S, is a poisonous gas with the odor of rotten eggs. The reaction for the formation of H,S from the elements is H,(g) + S;(rhombic) → H,S(g) > Use Hess's law to obtain the enthalpy change for this reac- tion from the following enthalpy changes: H,S(g) + 0,(g) H,(g) + ¿O,(g) S(rhombic) + O,(g) → H,0(g) + S0,(g); AH="-518 kJ - 242 kJ → SO,(g); AH = –297 kJ rig 17 Cenga Reserved. M → H,O(g); AH - 297 kJ
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![6.115 Hydrogen sulfide, H₂S, is a poisonous gas with the odor of rotten eggs. The reaction for the formation of H₂S from the elements is
\[ \text{H}_2(g) + \frac{1}{8}\text{S}_8(\text{rhombic}) \rightarrow \text{H}_2\text{S}(g) \]
Use Hess’s law to obtain the enthalpy change for this reaction from the following enthalpy changes:
\[ \text{H}_2\text{S}(g) + \frac{3}{2}\text{O}_2(g) \rightarrow \text{H}_2\text{O}(g) + \text{SO}_2(g); \Delta H = -518 \text{ kJ} \]
\[ \text{H}_2(g) + \frac{1}{2}\text{O}_2(g) \rightarrow \text{H}_2\text{O}(g); \Delta H = -242 \text{ kJ} \]
\[ \frac{1}{8}\text{S}_8(\text{rhombic}) + \text{O}_2(g) \rightarrow \text{SO}_2(g); \Delta H = -297 \text{ kJ} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F824a9fa1-de73-4e5c-9ec2-2636af2daa25%2F13825536-e685-43ca-b3b8-5388ea7a7b12%2F092skp_processed.png&w=3840&q=75)
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