prresponds to the pseudo code below. Assume hat the address for integer i is baseaddress+4 nd the address for a[0] is baseaddress+8. ssume that the baseaddress is stored in $gp. he code initializes i to 0; it then iterates from =O to i=9, setting a[i] = 32i in each iteration. To nake your code efficient, i must be loaded into a egister at the start, and it must be updated in nemory only after you've finished the for loop. or (i=0; i<10; i++) a[i] = 32*i; %3|
prresponds to the pseudo code below. Assume hat the address for integer i is baseaddress+4 nd the address for a[0] is baseaddress+8. ssume that the baseaddress is stored in $gp. he code initializes i to 0; it then iterates from =O to i=9, setting a[i] = 32i in each iteration. To nake your code efficient, i must be loaded into a egister at the start, and it must be updated in nemory only after you've finished the for loop. or (i=0; i<10; i++) a[i] = 32*i; %3|
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
![6. Write the MIPS assembly code that
corresponds to the pseudo code below. Assume
that the address for integer i is baseaddress+4
and the address for a[0] is baseaddress+8.
Assume that the baseaddress is stored in $gp.
The code initializes i to 0; it then iterates from
i=0 to i=9, setting a[i] = 32i in each iteration. To
make your code efficient, i must be loaded into a
register at the start, and it must be updated in
memory only after you've finished the for loop.
for (i=0; i<10; i++) a[i] = 32*i;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcfdec017-81a9-479e-be84-d9b6385220c5%2F26e606d6-91e1-4dcf-a90c-bb2f97c4f631%2Fj5qh79_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Write the MIPS assembly code that
corresponds to the pseudo code below. Assume
that the address for integer i is baseaddress+4
and the address for a[0] is baseaddress+8.
Assume that the baseaddress is stored in $gp.
The code initializes i to 0; it then iterates from
i=0 to i=9, setting a[i] = 32i in each iteration. To
make your code efficient, i must be loaded into a
register at the start, and it must be updated in
memory only after you've finished the for loop.
for (i=0; i<10; i++) a[i] = 32*i;
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