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6. Use Lewis structures to show the electron transfer that enables these ionic compounds to be formed: (a) Cao (b) NaBr

6. Use Lewis structures to show the electron transfer that enables these ionic compounds to be formed: (a) Cao (b) NaBr

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer number 6

4. The reaction for the combustion of propene is: 2 C3H5 + 902 - 6 CO2 + 6 H20 (a) If 15.0 g of C3H6 and 15.0 g of O2 are reacted, how many moles of H20 can be produced? (b) If 12.0 g of C3Hs and 25.0 g of O2 are reacted, how many moles of H20 can be produced? (c) If 5.0 mol of C3Hs and 15.0 mol of 02 are reacted to completion (until one reactant is completely used up), how many moles of CO2 can be produced? Which reactant is left over when the reaction has gone to completion in a closed container? 5. Use a periodic table to explain why metals tend to lose electrons and nonmetals tend to gain electrons? 6. Use Lewis structures to show the electron transfer that enables these ionic compounds to be formed: (a) Cao (b) NaBr
Transcribed Image Text:4. The reaction for the combustion of propene is: 2 C3H5 + 902 - 6 CO2 + 6 H20 (a) If 15.0 g of C3H6 and 15.0 g of O2 are reacted, how many moles of H20 can be produced? (b) If 12.0 g of C3Hs and 25.0 g of O2 are reacted, how many moles of H20 can be produced? (c) If 5.0 mol of C3Hs and 15.0 mol of 02 are reacted to completion (until one reactant is completely used up), how many moles of CO2 can be produced? Which reactant is left over when the reaction has gone to completion in a closed container? 5. Use a periodic table to explain why metals tend to lose electrons and nonmetals tend to gain electrons? 6. Use Lewis structures to show the electron transfer that enables these ionic compounds to be formed: (a) Cao (b) NaBr
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