6. ●● Three rugby players are pulling horizontally on ropes attached to a box, which remains stationary. Player 1 exerts a force F₁ equal to 1.00 × 10² N at an ngle 0₁ equal to 60.0° with respect to the + direction (Figure 4-27). Player 2 xerts a force F₂ equal to 2.00 × 10² N at an angle 02 equal to 37.0° with espect to the + direction. The view in the figure is from above. Ignore riction and note that gravity can be ignored in this problem. (a) Determine he force F3 exerted by player 3. State your answer by giving the components of F3 in the directions perpendicular to and parallel to the positive lirection. (b) Redraw the diagram and add the force F3 as carefully as you an. (c) Player 3's rope breaks, and player 2 adjusts by pulling with a force of nagnitude F₂ equal to 1.50 × 10² N at the same angle as before. In which lirection is the acceleration of the box relative to the + direction shown? (d) n part (c) the magnitude of the acceleration is measured to be 10.0 m/s². What is the mass of the box? Example 4-2 0₁ F₁ 1 F₂ 0₂ X 3e, © 2021 W. H. Freeman and Company Freedman, College Physics,

6. ●● Three rugby players are pulling horizontally on ropes attached to a box, which remains stationary. Player 1 exerts a force F₁ equal to 1.00 × 10² N at an ngle 0₁ equal to 60.0° with respect to the + direction (Figure 4-27). Player 2 xerts a force F₂ equal to 2.00 × 10² N at an angle 02 equal to 37.0° with espect to the + direction. The view in the figure is from above. Ignore riction and note that gravity can be ignored in this problem. (a) Determine he force F3 exerted by player 3. State your answer by giving the components of F3 in the directions perpendicular to and parallel to the positive lirection. (b) Redraw the diagram and add the force F3 as carefully as you an. (c) Player 3's rope breaks, and player 2 adjusts by pulling with a force of nagnitude F₂ equal to 1.50 × 10² N at the same angle as before. In which lirection is the acceleration of the box relative to the + direction shown? (d) n part (c) the magnitude of the acceleration is measured to be 10.0 m/s². What is the mass of the box? Example 4-2 0₁ F₁ 1 F₂ 0₂ X 3e, © 2021 W. H. Freeman and Company Freedman, College Physics,

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 11.8 lb object has the acceleration components m m ax 0,= (0.55) + (0.73), ay=(11.7) - (0.95) What…

Q: The force acting on an object is given by F = (6x - 10) N, where x is in meters. b My Questions |…

A: The force Fx is given as, Fx=6x-10 N............ (1)

Q: a) Three forces F1, F2 and F3 keep a point mass M in equilibrium. If F2 = 100 N, find F1 & F; 20…

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: When you apply a constant force to an object does the object move at a constant velocity or does its…

A: According to the newtons second law of motion:Force on a body is equal to the rate of change of…

Q: If the acceleration of a 1.0 kg moving particle by a force F is a = 3i +4j m/s^2, the magnitude of…

Q: A 305-pound box is placed on a ramp that is inclined 22.3°. (a) Find the magnitude of the force…

A: A box placed on an inclined ramp, Mass of block, m = 305 pound Force required to stop the block…

Q: 5. A 3.00-kg object is moving in a plane, with its x and y coordinates given by x = 5t2 -1 and y =…

Q: Two forces F, and F, act on a 8.40-kg object. F, = 30.0 N and F, = 16.0 N. 90,0 60.0 a (a) Find the…

A: Given : m = 8.40 kg F1 = 30 N F2 = 16 N

Q: Question 6) A crane lifts a box of mass M with an initial acceleration a. Determine the force on…

A: Page 1

Q: None

A: Step 1:Step 2:Certainly. I'll explain the solution part by part, going through each step in…

Q: A car (m= 1900 kg) is parked on a road that rises 12° above the horizontal. What are the magnitudes…

A: Given value--- Mass = 1900 kg. Angle = 12 degree We have to find--- Normal force? Static friction…

Q: A (10 kg) block sits on top of an plane inclined by (32 degrees) to the horizontal. There is a…

A: M = 10 kg Φ = 32 ⁰ μ = 0.1 H = 4 m sinΦ = H/d => d = H/SinΦ => d = 4/Sin(32) = 4/0.529…

Q: Torce constant 1.00 × 10˚ N/m is free to move on a frictionless horizontal surface. If the object is…

A: Step 1: for x= 0.1 mF= -100*0.1= -10 N, a= F/m = -10 m/s2 Step 2: for x= 0.05 mF= -100*0.05= -5 N,…

Q: ind the tension in an elevator cable if the 1 700-kg elevator is descending with an acceleration of…

A: Given: The acceleration of the elevator is 2.4 m/s2 downward. The mass of the elevator is 1700 kg.

Q: hen the astronaut enters the ISS (International Space Static I," where the only force acting on her…

A: When an astronaut enters the International Space Station (ISS), they experience a state known as…

Q: For the cart travelling down the incline, in which direction does the friction force act? (The…

A: Given, The cart traveling down the incline and the direction of motion is in the positive…

Q: Two forces F1 and F2 act on a 7.40-kg object: F- 40.0 N and F2 10.0 N. 90.0° 60.0 (a) Find the…

Q: Two forces F, and F, act on a 6.80-kg object. F, - 40.0 N and F,- 14.0 N. 90.0° 60.0° (a) Find the…

A: Given: The mass of the object is, m=6.80 kg. Force, F1=40.0 N. Force F2=14.0 N Introduction: When…

Q: A student applies a 100 N force at an angle 30° below the horizontal to a block causing the block to…

A: Given data: Applied force (F) = 100 N Angle (θ) = 30° below the horizontal Speed is constant…

Q: Part of a roller-coaster ride involves coasting down an incline and entering a loop 7.30 m in…

A: Given data *The given diameter is d = 7.30 m *The acceleration due to the gravity is g = 9.8 m/s2…

Q: Three blocks on a frictionless horizontal surface are in contact with each other. A force F is…

Q: A person brings a box onto an elevator. She places the box on the elevator floor. As the elevator…

Q: Three forces Fi = 5 i– 8.66 j N, F2 = 3 jN and F; are acting on an 8 kg body in free space. Find F3…

Q: 4. Figure 3 shows two force vectors acting on a 15kg object. No other forces act on the object! a.…

Concept explainers

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

Question

36... Three rugby players are pulling horizontally on ropes attached to a box,
which remains stationary. Player 1 exerts a force F₁ equal to 1.00 × 10² N at an
angle ₁ equal to 60.0° with respect to the + direction (Figure 4-27). Player 2
exerts a force F2 equal to 2.00 × 10² N at an angle 02 equal to 37.0° with
respect to the + direction. The view in the figure is from above. Ignore
friction and note that gravity can be ignored in this problem. (a) Determine
the force F3 exerted by player 3. State your answer by giving the components
of F3 in the directions perpendicular to and parallel to the positive a
direction. (b) Redraw the diagram and add the force F3 as carefully as you
can. (c) Player 3's rope breaks, and player 2 adjusts by pulling with a force of
magnitude F₂ equal to 1.50 × 10² N at the same angle as before. In which
direction is the acceleration of the box relative to the + direction shown? (d)
In part (c) the magnitude of the acceleration is measured to be 10.0 m/s².
What is the mass of the box? Example 4-2
0₂
0₁
F₁
Figure 4-27 Problem 36
№°º°
Freedman, College Physics, 3e, © 2021
W. H. Freeman and Company

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Two forces act on an 5 kg object: F1 = 60N applied at the origin in the direction of positive x- axis, and F2 = 40N, also applied at the origin but in the direction of positive y- axis. Calculate the magnitude of object's acceleration
Write Newton's laws for a static system (1) EF, = mg sin 0 – µ̟n = 0 in component form. The gravity force has two components. (2) EF, = n - mg cos 0 = 0 Rearrange Equation (2) to get an n = mg cos e expression for the normal force n. Substitute the expression for n into EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ, Equation (1) and solve for tan 0. Apply the inverse tangent function to tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3° get the answer. LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. smaller component of gravitational force along the ramp…
-> Two forces FA and FB are applied to an object whose mass is 13.9 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.535 m/s². However, when FA points due east and FB points due west, the acceleration is 0.417 m/s², due east. Find (a) the magnitude of FA and (b) the magnitude of FB. → (a) Number in (b) Number i Units Units m/s m/s
Ti A mover is loading a truck. He is pushing a 180 kg appliance on a frictionless dolly up a ramp inclined 25° above the horizontal. What are the I and || components of the weight of the appliance? Fg,1 1598.73 N. %3D Fg, = N. %3D What is the normal force on the appliance? FN = 1598.73 N. %3D What force must the mover exert parallel to the ramp to keep the box from moving? Fp = N. What force must he exert parallel to the ramp to accelerate it up the ramp at 0.7 m/s? Fp = 871.5 N. %3D
Fnorm Fapp = 15 N арp 45° Firiet =- 5 kg gray Assuming that the 5-kg object experience no net force (in equilibrium). the following values will be Fnorm Fgrav = Coefficient of kinetic friction u = O Fnorm = 60.4 N, Ferav = 49.0 N, Coefficient of kinetic friction uk = 0.25. O Fnorm = 38.4 N. Fe =49.0 N. Coefficient of kinetic friction u = 0.28. %3D grav O Fnorm = 49.0 N, Fgrav = 49.0 N, Coefficient of kinetic friction u = 0.22. Fnorm = 9.8 N, Ferav = 98.0 N, Coefficient of kinetic friction u = 0.56. Next
Ch.4 #55 . Please see attached image for Physics question . Thank you
Two forces F, and F2 act on a 5.40-kg object. F1 = 25.0 N and F2 = 13.0 N. a (a) Find the acceleration of the object for the configuration of forces shown in Figure (a). magnitude m/s2 direction ° (counterclockwise from F,) (b) Find the acceleration of the object for the configuration of forces shown in Figure (b). magnitude m/s? direction ° (counterclockwise from F,)
Two forces F₁ and F2 act on a 8.20-kg object. F₁ = 1 m 90.0° a F₁ 30.0 N and F2 m = 16.0 N. 60.0⁰ F₁ b (a) Find the acceleration of the object for the configuration of forces shown in Figure (a). magnitude m/s² direction • (counterclockwise from F₁) (b) Find the acceleration of the object for the configuration of forces shown in Figure (b). m/s² magnitude direction • (counterclockwise from F₁)