6. The water gas shift reaction shown below can be used to produce hydrogen from water and coal. Given the data in the following table, which experiment will proceed in the forward direction to produce more hydrogen? Under the experimental conditions, Ke = 25 for this reaction. H2O(g) + CO(g) 5 H:(g) + CO2(g) Initial Concentrations (mol/L) Experiment [H;O] [CO] 0.030 [CO] [H2] I 0.030 II 0.030 0.030 III 0.020 0.020 0.050 0.040 IV 0.030 0.020 0.030 0.020 I only b. II only I and III d. I, III, and IV e. I and IV а. с.
6. The water gas shift reaction shown below can be used to produce hydrogen from water and coal. Given the data in the following table, which experiment will proceed in the forward direction to produce more hydrogen? Under the experimental conditions, Ke = 25 for this reaction. H2O(g) + CO(g) 5 H:(g) + CO2(g) Initial Concentrations (mol/L) Experiment [H;O] [CO] 0.030 [CO] [H2] I 0.030 II 0.030 0.030 III 0.020 0.020 0.050 0.040 IV 0.030 0.020 0.030 0.020 I only b. II only I and III d. I, III, and IV e. I and IV а. с.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Water Gas Shift Reaction: Producing Hydrogen from Water and Coal**
The water gas shift reaction, represented by the equation below, can be used to generate hydrogen:
\[ \text{H}_2\text{O(g)} + \text{CO(g)} \rightleftharpoons \text{H}_2\text{(g)} + \text{CO}_2\text{(g)} \]
Given the experimental conditions and the equilibrium constant (\( K_c = 25 \)), we can determine which experiment will proceed in the forward direction to produce more hydrogen. The initial concentrations (in mol/L) of the reactants and products for each experiment are provided in the table below:
**Initial Concentrations (mol/L)**
| Experiment | [H₂O] | [CO] | [H₂] | [CO₂] |
|------------|-------|-------|-------|-------|
| I | 0.030 | 0.030 | 0 | 0 |
| II | 0 | 0 | 0.030 | 0.030 |
| III | 0.020 | 0.020 | 0.050 | 0.040 |
| IV | 0.030 | 0.020 | 0.030 | 0.020 |
**Question:** Which experiment(s) will proceed in the forward direction to produce more hydrogen?
**Options:**
a. I only
b. II only
c. I and III
d. I, III, and IV
e. I and IV
To answer this question, we compare the initial reaction quotient, \( Q_c \), to the equilibrium constant, \( K_c \). The reaction will proceed in the forward direction if \( Q_c < K_c \).
For each experiment, \( Q_c \) is calculated using:
\[ Q_c = \frac{[\text{H}_2][\text{CO}_2]}{[\text{H}_2\text{O}][\text{CO}]} \]
By evaluating each option and considering the given \( K_c \), we can determine that:
- In Experiment I:
\[ Q_c = \frac{(0)(0)}{(0.030)(0.030)} = 0 \]
Since \( 0 < 25 \), Experiment I will proceed in the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc31825ca-e532-4346-8c67-c6f0bc8ad95c%2F7d1e4b53-983f-4cc8-8776-9ae50d63cf27%2Fbtj1lt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Water Gas Shift Reaction: Producing Hydrogen from Water and Coal**
The water gas shift reaction, represented by the equation below, can be used to generate hydrogen:
\[ \text{H}_2\text{O(g)} + \text{CO(g)} \rightleftharpoons \text{H}_2\text{(g)} + \text{CO}_2\text{(g)} \]
Given the experimental conditions and the equilibrium constant (\( K_c = 25 \)), we can determine which experiment will proceed in the forward direction to produce more hydrogen. The initial concentrations (in mol/L) of the reactants and products for each experiment are provided in the table below:
**Initial Concentrations (mol/L)**
| Experiment | [H₂O] | [CO] | [H₂] | [CO₂] |
|------------|-------|-------|-------|-------|
| I | 0.030 | 0.030 | 0 | 0 |
| II | 0 | 0 | 0.030 | 0.030 |
| III | 0.020 | 0.020 | 0.050 | 0.040 |
| IV | 0.030 | 0.020 | 0.030 | 0.020 |
**Question:** Which experiment(s) will proceed in the forward direction to produce more hydrogen?
**Options:**
a. I only
b. II only
c. I and III
d. I, III, and IV
e. I and IV
To answer this question, we compare the initial reaction quotient, \( Q_c \), to the equilibrium constant, \( K_c \). The reaction will proceed in the forward direction if \( Q_c < K_c \).
For each experiment, \( Q_c \) is calculated using:
\[ Q_c = \frac{[\text{H}_2][\text{CO}_2]}{[\text{H}_2\text{O}][\text{CO}]} \]
By evaluating each option and considering the given \( K_c \), we can determine that:
- In Experiment I:
\[ Q_c = \frac{(0)(0)}{(0.030)(0.030)} = 0 \]
Since \( 0 < 25 \), Experiment I will proceed in the
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