21. The following equilibrium equation below is important in the productionof sulfuric acid. Product yield can be increased by *2SO2@) + O2ig) 2SO) AH = -198kJremoving [SO2] from the system.removing [02] from the system.O decreasing temperature of the system.increasing the volume of the reaction vessel.O decreasing the pressure of the system. 20. In the production of ammonia, which of the following conditions willincrease product yield? *N2(g) + 3H2(g) = AH = -92 kJ mol12NH3(9)increasing the pressureincreasing (NH3]O decreasing [N2]adding a catalystsincreasing the volume of the vessel

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20. In the production of ammonia, which of the following conditions will increase product yield? * N2(g) + 3H2(g) = 2NH3(g) AH: = -92 kJ mol1 O increasing the pressure O increasing [NH3] O decreasing [N2] O adding a catalysts increasing the volume of the vessel

20. In the production of ammonia, which of the following conditions will increase product yield? * N2(g) + 3H2(g) = 2NH3(g) AH: = -92 kJ mol1 O increasing the pressure O increasing [NH3] O decreasing [N2] O adding a catalysts increasing the volume of the vessel

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the following system at equilibrium where AH° = -111 kJ, and K = 0.159, at 723 K. %3D %3D N2(g) + 3H2(g) =2NH3(g) When 0.22 moles of H2(g) are added to the equilibrium system at constant temperature: The value of Kc The value of Qc. Kc. The reaction must O run in the forward direction to restablish equilibrium. O run in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of N2 will Submit Answer Retry Entire increase. roup attempts remaining decrease. remain the same.
To manufacture S03 with the reaction 2S02(g) + 02 - > 2S03(g) A H° = -99 kJ, one way to increase the equilibrium S03 would be to O decrease oxygen O decrease SO2 increase pressure increase temperature
Can you explain (not graded )
In a suitable reaction vessel, pieces of graphite are mixed with carbon dioxide gas at 1.00 atm and 1000 K. Which two of the following changes will shift the reaction towards the products? kJ.mol-1 C(s) + CO₂ (g) 2 CO(g) → (A) increase the volume (B) decrease the temperature (C) decrease partial pressure of CO(g) (D) decrease partial pressure of CO₂(g) ΔΗ = 172
N2(g) + 3H2 (g) = 2NH3 (g) AH°pn =-92 kJ Which of the following changes would cause the value of K for this reaction to increase? You can choose any combination of answers. Decreasing the volume of the reaction container. Heating the reaction container Cooling the reaction container Adding Helg) to the reaction container removing NH3(g) from reaction container.
When 1.00 mol of H2O and 1.00 mol of CO are introduced into an empty 1.00 L container at 960 K and allowed to come to equilibrium, the mixture contains 0.422 mol of water vapor. Write the equilibrium expression for the reaction and calculate the value of Kc
For the following equation, how would you increase the amount of product? CO(g) + H2(g) → C(s) + H₂O(g) AH = -131.5 kJ/mole Remove carbon, decrease PH₂O, increase temperature, increase PCO, increase PH₂, decrease total pressure. Remove carbon, decrease PH₂O, decrease temperature, increase PCO, increase PH₂, decrease total pressure. Remove carbon, decrease PH₂O, decrease temperature, increase PCO, increase PH₂, increase total pressure. CDecrease PH₂O, decrease temperature, increase PCO, increase PH₂, increase total pressure. CDecrease PH₂O, decrease temperature, increase PCO, increase PH2, decrease total pressure. CDecrease PH₂O, increase temperature, increase PCO, increase PH₂, increase total pressure. Decrease PH₂O, increase temperature, increase PCO, increase PH₂, decrease total pressure. Remove carbon, decrease PH₂O, increase temperature, increase PCO, increase PH₂, increase total pressure.
The below reaction was found to have AH = -3606 kJ mol-1 and AS = 33 J mol- K-1. What is AG for this reaction at 100.2 °C? 90,(g) + 2CH;CHCH,(g) – 6CO,(g) + 6H2O(g) Oa. -3618 kJ mol-1 Ob. -3609 kJ mol-1 Oc. -15927 kJ mol-1 Od. -3573 kJ mol-1 Oe. -3594 kJ mol-1
A reaction vessel initially contains 6.30 atm of A and 2.10 atm of B. A reaction occurs according to the equation:2A(g)+B(g)⇆2C(g)2A(g)+B(g)⇆2C(g)When equilibrium is reached, the total pressure is found to be 6.51 atm. What is the equilibrium constant Kp?Please enter your response to three significant figures using decimal notation.
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