6. The definition of the first derivative is f(x+h)+f(x) E. f'(x) = F. f'(x) h f(x+h)-f(x) h f(x+h)+f(x) G. f(x) = lim h→0 h f(x+h)-f(x) H. f(x) = lim 7. If f(x) = x² + 2x – 1, what is the f'(x)? A. x² + 2 h→0 h В. 2х2 + 2 С. 2х + 2 D. 2x 8. Find the derivative of the following function: f (x) = x2 A. f'(x) = B. f'(x) = J C. f'(x) = %3D D. 2vx f'(x) = Vx 9. Given by f(x) = 3x4 + 2 and g(x) = vx, find f'(x) + g'(x) А. 12х3 + Vx B. 12x3 +÷x C. 12x* +xi D. 12x³ + x 10. Find f'(x) if f(x) = (2x² + 1)(x² – x) А. 8х3 — 6х2 + 2х — 1 С. 8х3 — бх2 — 2х — 1 В. 8х3 + бх2+ 2х — 1 D. 8x3 — бх2 + 2х + 1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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6. The definition of the first derivative is
f(x+h)+f(x)
E. f'(x) =
F. f'(x) =
h
f(x+h)-f(x)
h
f (x+h)+f(x)
G. f(x) = lim
h→0
f(x+h)-f(x)
h
H. f(x) = lim
7. If f(x) = x² + 2x – 1, what is the f'(x)?
A. x² + 2
h→0
h
-
В. 2х2 + 2
С. 2х + 2
D. 2x
1
8. Find the derivative of the following function: f (x) = x7
1
A. f'(x) =
B. f'(x) = J
C. f'(x) =
D.
2Vx
f'(x) = Vx
9. Given by f(x) = 3x4 + 2 and g(x) = Vx, find f'(x) + g'(x)
A. 12x3 + Vx
B. 12x³ +x
1
С. 12х3 + - х?
C. 12x³
D. 12x3 + x
2
(2x2 + 1)(x2 — х)
10. Find f'(x) if f(x)
А. 8х3 — бх?+ 2х — 1
С. 8х3 — бх2 — 2х — 1
В. 8х3 + 6х2+ 2х — 1
D. 8x3 - бx2+ 2х + 1
Transcribed Image Text:6. The definition of the first derivative is f(x+h)+f(x) E. f'(x) = F. f'(x) = h f(x+h)-f(x) h f (x+h)+f(x) G. f(x) = lim h→0 f(x+h)-f(x) h H. f(x) = lim 7. If f(x) = x² + 2x – 1, what is the f'(x)? A. x² + 2 h→0 h - В. 2х2 + 2 С. 2х + 2 D. 2x 1 8. Find the derivative of the following function: f (x) = x7 1 A. f'(x) = B. f'(x) = J C. f'(x) = D. 2Vx f'(x) = Vx 9. Given by f(x) = 3x4 + 2 and g(x) = Vx, find f'(x) + g'(x) A. 12x3 + Vx B. 12x³ +x 1 С. 12х3 + - х? C. 12x³ D. 12x3 + x 2 (2x2 + 1)(x2 — х) 10. Find f'(x) if f(x) А. 8х3 — бх?+ 2х — 1 С. 8х3 — бх2 — 2х — 1 В. 8х3 + 6х2+ 2х — 1 D. 8x3 - бx2+ 2х + 1
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